assert(true) 警告 signed/unsigned 不匹配
assert(true) warns of signed/unsigned mismatch
Visual Studio 2008，调试版本。这行C++
assert(true);
引起投诉
warning C4365: 'argument' : conversion from 'long' to 'unsigned int', signed/unsigned mismatch
将 true 替换为任何（有用的）布尔表达式时，警告仍然存在，即使是 1ul。
仅供参考，编译器文件 assert.h 是：
#define assert(_Expression) (void)( (!!(_Expression)) || (_wassert(_CRT_WIDE(#_Expression), _CRT_WIDE(__FILE__), __LINE__), 0) )
extern "C" _CRTIMP void __cdecl _wassert(_In_z_ const wchar_t * _Message, _In_z_ const wchar_t *_File, _In_ unsigned _Line);
如何在不抑制 所有 C4365 的情况下完全抑制此警告？是__LINE__的错吗？？
The bug report explains it very well:
This issue occurs because __LINE__ is of type long, and the assert
macro passes __LINE__ as an argument to the _wassert function, which
expects an unsigned int. When not compiling with /ZI, __LINE__ is a
constant expression, so the compiler can statically determine that the
conversion to unsigned int will result in the same value. When
compiling with /ZI, __LINE__ is not a constant expression, so the
compiler cannot statically determine that the conversion will result
in the same value and it issues warning C4365.
它还给出了一个解决方法：
As a workaround for this issue, I would recommend #undefing assert in
your source code, and re-#define-ing it, using the same definition as
in <assert.h>, but with a cast to suppress the warning.
请注意，此错误似乎已从 MSVC2015 开始修复。
Visual Studio 2008，调试版本。这行C++
assert(true);
引起投诉
warning C4365: 'argument' : conversion from 'long' to 'unsigned int', signed/unsigned mismatch
将 true 替换为任何（有用的）布尔表达式时，警告仍然存在，即使是 1ul。
仅供参考，编译器文件 assert.h 是：
#define assert(_Expression) (void)( (!!(_Expression)) || (_wassert(_CRT_WIDE(#_Expression), _CRT_WIDE(__FILE__), __LINE__), 0) )
extern "C" _CRTIMP void __cdecl _wassert(_In_z_ const wchar_t * _Message, _In_z_ const wchar_t *_File, _In_ unsigned _Line);
如何在不抑制 所有 C4365 的情况下完全抑制此警告？是__LINE__的错吗？？
The bug report explains it very well:
This issue occurs because
__LINE__is of type long, and the assert macro passes__LINE__as an argument to the _wassert function, which expects an unsigned int. When not compiling with/ZI,__LINE__is a constant expression, so the compiler can statically determine that the conversion to unsigned int will result in the same value. When compiling with/ZI,__LINE__is not a constant expression, so the compiler cannot statically determine that the conversion will result in the same value and it issues warning C4365.
它还给出了一个解决方法：
As a workaround for this issue, I would recommend #undefing assert in your source code, and re-#define-ing it, using the same definition as in
<assert.h>, but with a cast to suppress the warning.
请注意，此错误似乎已从 MSVC2015 开始修复。