如何从 Python 中的 subprocess.Popen 向 shell 脚本传递值

Question

我有以下内容：

myscript.py

#!/usr/bin/python
from threading import Thread
import time
import subprocess

subprocess.Popen("./hello.sh 1", shell=True)
subprocess.Popen("./hello.sh 2", shell=True)
subprocess.Popen("./hello.sh 3", shell=True)

hello.sh

echo "Hello From Shell Script "

输出为：

Hello From Shell Script 1
Hello From Shell Script 2
Hello From Shell Script 3

我想像这样在 for 循环中执行此操作：

for num in range(1,3):
    subprocess.Popen(['./hello.sh', str(num)], shell=True)

但是输出是：

Hello From Shell Script
Hello From Shell Script
Hello From Shell Script

如果我删除 shell=True 那么现在是：

subprocess.Popen(['./hello.sh', str(num)])

我得到以下信息：

Traceback (most recent call last):
  File "./myscript.py", line 12, in <module>
    subprocess.Popen(['./hello.sh', str(num)])
  File "/usr/lib64/python2.6/subprocess.py", line 623, in __init__
    errread, errwrite)
  File "/usr/lib64/python2.6/subprocess.py", line 1141, in _execute_child
    raise child_exception
OSError: [Errno 8] Exec format error

如何才能将正确的值传递给脚本？

Answer 1

改成如下：

>>> for num in range(1,3):
...     subprocess.Popen(['./hello.sh '+str(num)], shell=True)

Answer 2

如果您传递的是列表而不是字符串作为第一个参数，请不要使用 shell=True。

subprocess.Popen(['./hello.sh', str(num)])

如何从 Python 中的 subprocess.Popen 向 shell 脚本传递值

How to pass a value to shell script from subprocess.Popen in Python

python

bash

shell

subprocess