我如何从 CallLog 中获得 3 个最高号码

Question

如何根据拨打号码的总时长从 CallLog 中获取前三个号码？

例如，给定这些 calls/durations：

0123-2323 3 分钟
0123-2323 59 分钟
3232-3210 15 分钟

0123-2323 的总数是 totalmin=62。 3232-3210 是 totalmin=15.

我试过这段代码：

private String getCallDetails(){
    StringBuffer sb = new StringBuffer();
    Cursor managedCursor = managedQuery(CallLog.Calls.CONTENT_URI, null, null, null, null);
    int number = managedCursor.getColumnIndex(CallLog.Calls.NUMBER);
    int type = managedCursor.getColumnIndex(CallLog.Calls.TYPE);
    int date = managedCursor.getColumnIndex(CallLog.Calls.DATE);
    int duration = managedCursor.getColumnIndex(CallLog.Calls.DURATION);
    sb.append("Call Details :");
    while (managedCursor.moveToNext()){
        String phNumber = managedCursor.getString(number);
        String callType = managedCursor.getString(type);
        String callDate = managedCursor.getString(date);
        Date callDayTime = new Date(Long.valueOf(callDate));
        String callDuration = managedCursor.getString(duration);
        String dir = null;
        int dircode = Integer.parseInt(callType);
        switch (dircode) {
        case CallLog.Calls.OUTGOING_TYPE:
            dir = "OUTGOING";
            break;
        case CallLog.Calls.INCOMING_TYPE:
            dir = "INCOMING";
            break;
        case CallLog.Calls.MISSED_TYPE:
            dir = "MISSED";
            break;
        }
        sb.append("\nPhone Number:--- " + phNumber + " \nCall Type:--- "
                + dir + " \nCall Date:--- " + callDayTime
                + " \nCall duration in sec :--- " + callDuration);
        sb.append("\n----------------------------------");
    }
    managedCursor.close();
    return sb.toString();
}

Answer 1

创建地图并对其进行排序。根据通话时长获取您的联系人，并像这样获取您的前 3 位联系人。

 cc1=0;
 Map<String, Integer> sortedMapa = sortByComparator(topsmstreemap, DESC);
 for (Map.Entry<String, Integer> entry : sortedMapDeses.entrySet())
 {
 if(cc1<3) 
 {cc1++;
 }

我如何从 CallLog 中获得 3 个最高号码

How can i get 3 Top number from CallLog

android

calllog