使用 directshow 在桌面录制上翻转光标图标

Fliped cursor icon on desktop recording using directshow

使用Directshow.NET我开发了一个会记录桌面屏幕的应用程序,为了获得鼠标指针我们需要自己绘制鼠标指针。所以我在 BufferCB 中添加了 SampleGrabber adn 我写了下面的代码:

    public const Int32 CURSOR_SHOWING = 0x00000001;

    [StructLayout(LayoutKind.Sequential)]
    public struct ICONINFO
    {
        public bool fIcon;
        public Int32 xHotspot;
        public Int32 yHotspot;
        public IntPtr hbmMask;
        public IntPtr hbmColor;
    }

    [StructLayout(LayoutKind.Sequential)]
    public struct POINT
    {
        public Int32 x;
        public Int32 y;
    }

    [StructLayout(LayoutKind.Sequential)]
    public struct CURSORINFO
    {
        public Int32 cbSize;
        public Int32 flags;
        public IntPtr hCursor;
        public POINT ptScreenPos;
    }

    [DllImport("user32.dll")]
    public static extern bool GetCursorInfo(out CURSORINFO pci);

    [DllImport("user32.dll")]
    public static extern IntPtr CopyIcon(IntPtr hIcon);

    [DllImport("user32.dll")]
    public static extern bool DrawIcon(IntPtr hdc, int x, int y, IntPtr hIcon);

    [DllImport("user32.dll")]
    public static extern bool GetIconInfo(IntPtr hIcon, out ICONINFO piconinfo);

public int BufferCB(double SampleTime, IntPtr pBuffer, int BufferLen)
{
Graphics g;
Bitmap v;
v = new Bitmap(m_videoWidth, m_videoHeight, m_stride, System.Drawing.Imaging.PixelFormat.Format24bppRgb, pBuffer);            
g = Graphics.FromImage(v);
CURSORINFO cursorInfo;
cursorInfo.cbSize = Marshal.SizeOf(typeof(CURSORINFO));

if (GetCursorInfo(out cursorInfo))
{
    if (cursorInfo.flags == CURSOR_SHOWING)
    {
        var iconPointer = CopyIcon(cursorInfo.hCursor);
        ICONINFO iconInfo;
        int iconX, iconY;

        if (GetIconInfo(iconPointer, out iconInfo))
        {
            iconX = cursorInfo.ptScreenPos.x - ((int)iconInfo.xHotspot);
            iconY = cursorInfo.ptScreenPos.y - ((int)iconInfo.yHotspot);

            DrawIcon(g.GetHdc(), iconX, iconY, cursorInfo.hCursor);
            g.ReleaseHdc();
            g.Dispose();
            v.Dispose();                        
        }
    }
}
return 0;
}

此代码正在绘制鼠标光标,但光标在 Y 轴上翻转。

可能是因为在 BufferCB 中,如果我们在 Bitmap 中转换 pBuffer,那么该帧将在 Y 轴上翻转。为了解决这个问题,我通过在 BufferCB 内添加 v.RotateFlip(RotateFlipType.RotateNoneFlipY); 来翻转 Y 轴上的当前帧,此更改后鼠标指针在桌面录制视频中不可见。

如何翻转鼠标指针?

更新#1

我使用 Icon.ToBitmap() 将图标指针转换为 Icon 然后转换为 Bitmap 然后在 Y 轴上翻转,这是代码(感谢@Roman R.):

...
iconX = cursorInfo.ptScreenPos.x - ((int)iconInfo.xHotspot);
iconY = cursorInfo.ptScreenPos.y - ((int)iconInfo.yHotspot);

Icon ic = Icon.FromHandle(iconPointer);
Bitmap icon = ic.ToBitmap();
icon.RotateFlip(RotateFlipType.RotateNoneFlipY);
g.DrawImage(icon, iconX, iconY);
g.Dispose();
v.Dispose();
icon.Dispose();
ic.Dispose();  
...

我在上述修改中只遇到一个问题,有时我在第 Bitmap icon = ic.ToBitmap();

行得到 ArgumentException
  System.ArgumentException occurred
  HResult=-2147024809
  Message=Parameter is not valid.
  Source=System.Drawing
  StackTrace:
       at System.Drawing.Bitmap.FromHicon(IntPtr hicon)
  InnerException: 

我处理了所有使用的位图,但仍然出现此异常。

您还有另一种选择,即绘制正确的鼠标指针。只需将鼠标指针的 PNG 图片放入 BufferCB:

public int BufferCB(double SampleTime, IntPtr pBuffer, int BufferLen)
{
Graphics g;
Bitmap v;
v = new Bitmap(m_videoWidth, m_videoHeight, m_stride, System.Drawing.Imaging.PixelFormat.Format24bppRgb, pBuffer);            
g = Graphics.FromImage(v);
CURSORINFO cursorInfo;
cursorInfo.cbSize = Marshal.SizeOf(typeof(CURSORINFO));

if (GetCursorInfo(out cursorInfo))
{
    if (cursorInfo.flags == CURSOR_SHOWING)
    {
        var iconPointer = CopyIcon(cursorInfo.hCursor);
        ICONINFO iconInfo;
        int iconX, iconY;

        if (GetIconInfo(iconPointer, out iconInfo))
        {
            iconX = cursorInfo.ptScreenPos.x - ((int)iconInfo.xHotspot);
            iconY = cursorInfo.ptScreenPos.y - ((int)iconInfo.yHotspot);

            //DRAW STATIC POINTER IMAGE
            Bitmap pointerImage = new Bitmap('pointer.png');
            g.DrawImage(pointerImage,iconX,iconY);

            g.Dispose();
            v.Dispose();                        
        }
    }
}
return 0;
}

这里的问题是您的 BufferCB 实施。您创建了一个临时的 Graphics/Bitmap 对象,以便可以使用光标覆盖对其进行更新。您将此位图上下颠倒,并应用图标的正常绘制将其翻转。

您需要考虑到通过 BufferCB 回调获得的 24 位 RGB 缓冲区行的正常顺序是从下到上; Bitmap constructor 期望的行顺序是相反的。您需要以相反的顺序将行转移到 Bitmap 中,然后将它们分别取回。我不确定负步幅是否有效,大概不会。或者简单地覆盖预先翻转的光标,以补偿翻转的背景和覆盖坐标。