SWIFT 中的 UIFont 扩展

Question

我正在尝试为 Swift 书面项目编写 UIFont 扩展。我收到错误 'AnyObject is not convertible to String'。我该如何解决这个问题。这是我所做的

 func listAllFontsOnSystem(){

    var familyNames = NSArray(array: UIFont.familyNames())
    var fontNames = []
    var indFamily, indFont : NSInteger
    for (indFamily = 0 ; indFamily<familyNames.count; ++indFamily){
    //Error on next line
        fontNames = NSArray(array: UIFont.fontNamesForFamilyName(familyNames .objectAtIndex(indFamily)))
        for indFont = 0; indFont<fontNames.count; ++indFont{
        print(fontNames.objectAtIndex(indFont))
        }
    }
}

Answer 1

试试这个代码。 UIFont.familyNames returns AnyObject 的数组即 [AnyObject]。它必须转换为字符串数组，即 [String].

func listAllFontsOnSystem(){

    var familyNames =  UIFont.familyNames() as [String]
    for familyName in familyNames {
        let fontNames = UIFont.fontNamesForFamilyName(familyName) as [String]
        for fontName in fontNames {
            println(fontName)
        }
    }
}

Answer 2

UIFont.fontNamesForFamilyName(familyNames.objectAtIndex(indFamily))
                              ^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^

objectAtIndex，是 Objective-C 方法 returns id，returns Swift 中的 AnyObject 实例，而不是字符串。您可以 "cast" 将其转换为 String。

fontNames = NSArray(array: UIFont.fontNamesForFamilyName(
               familyNames.objectAtIndex(indFamily) as String))

这是 Swift 少 Objective-C 的版本的样子：

class func listAllFontsOnSystem2(){
    let familyNames = UIFont.familyNames() as [String]
    for familyName in familyNames {
        let fontNames = UIFont.fontNamesForFamilyName(familyName) as [String]
        for fontName in fontNames {
            println(fontName)
        }
    }
}

SWIFT 中的 UIFont 扩展

UIFont extension in SWIFT

uifont

ios

swift