PHP 单击提交按钮时排序 table

Question

我希望能够在单击提交按钮时在字段中将我的 table 排序为 ASC。

我使用数组函数从 SQL 数据库中获取信息，我尝试制作排序函数，但是当我单击 'submit' 时没有任何反应。

这是我创建提交按钮的尝试：

 <h1> Courses </h1>
<form name="Table Properties" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
Order by Week
<button type="submit" name="week" class="button" <?php echo $value='1'; ?>"> Sort Week </button>
</form>
<?php 
if(isset($_POST['week'])){
        $query="SELECT * FROM `classes` ORDER BY `classes`.`week` ASC";
   }

当我点击提交时 table 保持不变。

这是我的 table 连接信息

$con = mysql_connect("host", "username", "password");
if (!$con) 
{
    die('Could not connect: ' . mysql_error());
}
mysql_select_db("username", $con);
$sql = "SELECT * FROM `classes`";
$myData = mysql_query($sql, $con);
echo "<table border=1>
<tr>
<th> Name 1 </th>
<th> Name 2 </th>
<th> Name 3 </th>
<th> Name 4 </th>
</tr>";
while ($record = mysql_fetch_array($myData)){
    echo "<tr>";
    echo"<td>" . $record['name 1'] . "</td>";
    echo"<td>" . $record['week'] . "</td>";
    echo"<td>" . $record['name 3'] . "</td>";
    echo"<td>" . $record['name 4'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysql_close($con);
}
?>

我过去问过类似的问题，但我认为由于缺乏完整的信息，他们误解了。

Answer 1

将 ORDER BY 子句添加到 "table connect information" 中的 SQL 语句。

Answer 2

您必须更改您的原始查询。 $sql = "SELECT * FROM classes";

让我们总结一下：

您的表格：

<h1> Courses </h1>
<form name="Table Properties" method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>">
Order by Week
<button type="submit" name="week" class="button" <?php echo $value='1'; ?>"> Sort Week </button>
</form>

提交时：

<?php

$orderString = ''; // default 
if (isset($_POST['week'])){
    $orderString = "`classes`.`week` ASC";
}

您的显示：

$con = mysql_connect("host", "username", "password");
if (!$con) 
{
    die('Could not connect: ' . mysql_error());
}
mysql_select_db("username", $con);
$sql = "SELECT * FROM `classes`";
// now check order
if ($orderString !== '') {
    // Concatenate
    $sql .= ' ORDER BY ' . $orderString;
}
$myData = mysql_query($sql, $con);
echo "<table border=1>
<tr>
<th> Name 1 </th>
<th> Name 2 </th>
<th> Name 3 </th>
<th> Name 4 </th>
</tr>";
while ($record = mysql_fetch_array($myData)){
    echo "<tr>";
    echo"<td>" . $record['name 1'] . "</td>";
    echo"<td>" . $record['week'] . "</td>";
    echo"<td>" . $record['name 3'] . "</td>";
    echo"<td>" . $record['name 4'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysql_close($con);
}
?>

Answer 3

试试这个代码

$con = mysql_connect("host", "username", "password");
if (!$con) 
{
    die('Could not connect: ' . mysql_error());
}
mysql_select_db("username", $con);
$sql = "SELECT * FROM `classes`";

if(isset($_POST['week'])){
        $sql="SELECT * FROM `classes` ORDER BY `classes`.`week` ASC";
   }

$myData = mysql_query($sql, $con);
echo "<table border=1>
<tr>
<th> Name 1 </th>
<th> Name 2 </th>
<th> Name 3 </th>
<th> Name 4 </th>
</tr>";
while ($record = mysql_fetch_array($myData)){
    echo "<tr>";
    echo"<td>" . $record['name 1'] . "</td>";
    echo"<td>" . $record['week'] . "</td>";
    echo"<td>" . $record['name 3'] . "</td>";
    echo"<td>" . $record['name 4'] . "</td>";
    echo "</tr>";
}
echo "</table>";
mysql_close($con);
}
?>

Answer 4

您定义您的操作，当提交按钮被按下时，但实际上并不使用它。表格后不需要 php 部分。尝试编辑您的 table 连接信息：

...
mysql_select_db("username", $con);
if(isset($_POST['week'])){
    $sql="SELECT * FROM `classes` ORDER BY `classes`.`week` ASC";
}
else{
    $sql = "SELECT * FROM `classes`";
}
$myData = mysql_query($sql, $con);
...

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