在 C++ 中读取带有模式的文件

Question

我想读取一个有模式的文件，我想在最后保存值。例如。如果它是一个房间，它具有三个必须保存的值大小值等等。

我要读取的文件是这样的：

room
{
    size 5 3.3 6
    wallpaper
    {
        texture flower.bmp
        tiling 3 1
    }
}
object vase
{
    translation 0.2 0 0.5
    roation 0 1 0 0
    scaling 1 1 1
    model vase.obj
    parent tisch
}
Object tisch
{
    translation 2.0 0 3
    roation 0 1 0 45
    scaling 1.5 1 1
    model tisch.obj
    parent NULL
}

我是这样开始的。如何读取和保存房间和对象的下一行？

fstream osh("/Users/torhoehn/Desktop/room.osh", ios::in);
    string line;

    if (osh.good()) {
        while (getline(osh, line, '[=11=]')) {
            if (line.compare("room")) {
                cout << "Found room" << endl;

            }

            if (line.compare("object")) {
                cout << "Found object" << endl;
            }
        }
        osh.close();

    }

Answer 1

使用输入运算符：

string noun, junk;

while(osh >> noun) {
  if (noun == "room") {
    cout << "Found room ";
    osh >> junk >> junk;  // for the brace and "size"
    float length, width, height;
    osh >> length >> width >> height;
    cout << length << " long and " << breadth << " wide" << endl;
    ...
  }

  if ( noun == "object" ) {
    osh >> noun;            // what kind of object?
    if ( noun == "vase" ) {
      cout << "found vase ";
      osh >> junk >> junk;
      float translationX, translationY, translationZ;
      osh >> translationX >> translationY >> translationZ;
      ...
    }
    if ( noun == "tisch" ) {
      cout << "found tisch ";
      osh >> junk >> junk;
      float translationX, translationY, translationZ;
      osh >> translationX >> translationY >> translationZ;
      ...
    }
    ...
  }     // object
  ...

在你完美地工作之后，你可以考虑为 Room class、Vase class 等编写构造函数，等等，这将使代码更清晰。

在 C++ 中读取带有模式的文件

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