通过从字典中获取列表值来更改列表值 (Python)

Question

所以我的列表如下所示：

['One', 'Two', 'Three', 'Four']
['Five', 'Six', 'Seven']

所以，一个包含 2 个元素的列表

lst = [['One', 'Two', 'Three', 'Four'], ['Five', 'Six', 'Seven']]

然后我还有一个字典，我是这样声明的：

numberDict = dict()

numberDict["One"] = "First"
numberDict["Two"] = "Second"
numberDict["Three"] = "Third"
numberDict["Four"] = "Fourth"
numberDict["Five"] = "Fifth"
numberDict["Six"] = "Sixth"
numberDict["Seven"] = "Seventh"

我的问题：如何让列表看起来像这样？要用字典中的值替换它的值？

lst = [['First', 'Second', 'Third', 'Fourth'], ['Fifth', 'Sixth', 'Seventh']]

Answer 1

使用列表理解：

>>> list_of_list = [['One', 'Two', 'Three', 'Four'], ['Five', 'Six', 'Seven']]
>>> [[numberDict.get(value, "") for value in lst] for lst in list_of_list]
[['First', 'Second', 'Third', 'Fourth'], ['Fifth', 'Sixth', 'Seventh']]

顺便说一句，请注意您也可以一次性初始化 numbersDict

>>> numbers_dict = {"One": "First",
...     "Two": "Second",
...     "Three": "Third",
...     "Four": "Fourth",
...     "Five": "Fifth",
...     "Six": "Sixth",
...     "Seven": "Seventh"}

通过从字典中获取列表值来更改列表值 (Python)

Changing values of a list by getting them from a dictionary (Python)

python

dictionary

list-comprehension

list