如何打印导致 fswatch 执行某些操作的文件路径

Question

我使用 fswatch 在文件更改时执行一些操作。我使用以下命令：

fswatch -o -r '.' | while read MODFILE
do
    echo 'Some file changed, so take some action'
done

这工作正常，如果我更改几个文件，我会在终端中看到以下内容：

Some file changed, so take some action
Some file changed, so take some action
Some file changed, so take some action
etc.

但我也想知道究竟是哪个文件导致了该操作。所以我查看了 fswatch 手册页，其中显示如下：

fswatch writes a record for each event it receives containing:
     -       The timestamp when the event was received (optionally).
     -       The path affected by the current event.
     -       A space-separated list of event types (see EVENT TYPES ).

但如前所述，我的终端中没有看到任何列出的内容。有人知道我如何显示“受当前事件影响的路径。”吗？

欢迎所有提示！

Answer 1

当然，使用这个：

fswatch --batch-marker=EOF -xn . | while read file event; do 
   echo $file $event
   if [ $file = "EOF" ]; then 
      echo TRIGGER
   fi
done

如果您想将受影响文件的名称保存在列表中，您可以这样做：

#!/bin/bash
fswatch --batch-marker=EOF -xn . | while read file event; do
    if [ $file = "EOF" ]; then
       echo TRIGGER
       echo Files: "${list[@]}"
       list=()
    else
       echo $file $event
       list+=($file)
    fi
done

如何打印导致 fswatch 执行某些操作的文件路径

How to print file path that caused fswatch to do something

linux

macos

inotify

inotifywait

fswatch