PHP 枚举层次结构
PHP Enum Hierarchy
我想为我的 PHP 应用程序创建分层枚举,并想到了
abstract class User_Roles extends Enum {
const Administrator = "";
const Account_Manager = "Administrator";
const BlogAuthor = "Account_Manager";
const CommentManager = "Account_Manager";
}
我正在使用这个 Enum-Class:SO
所以每个 child 都有他的 parent 节点值。
我会这样做:
$constants = $reflector->getConstants();
foreach ($constants as $key => $value) {
if ($value == "") {
$returnHierarchy[$key] = array();
continue;
}
$returnHierarchy[][$value] = $key;
}
但是我想创建的多维数组有一些问题。
所以它应该是这样的:
[Administrator]
{
[Account_Manager]
{
[BlogAuthor]
[CommentManager]
}
}
但我最终会遇到这样的事情:
array(4) (
[Administrator] => array(0)
[0] => array(1) (
[Administrator] => (string) Account_Manager
)
[1] => array(1) (
[Account_Manager] => (string) BlogAuthor
)
[2] => array(1) (
[Account_Manager] => (string) CommentManager
)
)
有没有我误解或忽略的地方?
如果你的 $value
角色已经存在,你必须循环 $contstants
并在你的 $returnHierarchy
中搜索 如果没有则创建新角色
要在数组中搜索,您必须使用递归函数,它将 return 匹配子数组索引引用
// IMPORTANT: it return reference function mae mast start with &
function &searchKeyInArray($key, &$array){
$matchedArrayReffarance = null;
if( !isset($array[$key]) ){
foreach ($array as &$sub){
if(is_array($sub)){
$matchedArrayReffarance = &searchKeyInArray($key, $sub);
}
}
}else{
$matchedArrayReffarance = &$array;
}
return $matchedArrayReffarance;
}
然后简单地使用上面定义的 searchKeyInArray
你可以实现你正在寻找的东西
$returnHierarchy = array();
// This is example, in your case it is: $constants = $reflector->getConstants();
$constants = array(
'Administrator' => "",
'Account_Manager' => "Administrator",
'BlogAuthor' => "Account_Manager",
'CommentManager' => "Account_Manager",
);
foreach ($constants as $key => $value) {
$matchArray = &searchKeyInArray($value, $returnHierarchy);
if( isset($matchArray) ){
$matchArray[$value][$key] = array();
}else{
$returnHierarchy[$key] = array();
}
}
var_dump($returnHierarchy);
$returnHierarchy
的var_dump将是
array(1) {
["Administrator"]=> &array(1) {
["Account_Manager"]=> array(2) {
["BlogAuthor"]=> array(0) { }
["CommentManager"]=> array(0) { }
}
}
}
我想为我的 PHP 应用程序创建分层枚举,并想到了
abstract class User_Roles extends Enum {
const Administrator = "";
const Account_Manager = "Administrator";
const BlogAuthor = "Account_Manager";
const CommentManager = "Account_Manager";
}
我正在使用这个 Enum-Class:SO
所以每个 child 都有他的 parent 节点值。
我会这样做:
$constants = $reflector->getConstants();
foreach ($constants as $key => $value) {
if ($value == "") {
$returnHierarchy[$key] = array();
continue;
}
$returnHierarchy[][$value] = $key;
}
但是我想创建的多维数组有一些问题。
所以它应该是这样的:
[Administrator]
{
[Account_Manager]
{
[BlogAuthor]
[CommentManager]
}
}
但我最终会遇到这样的事情:
array(4) (
[Administrator] => array(0)
[0] => array(1) (
[Administrator] => (string) Account_Manager
)
[1] => array(1) (
[Account_Manager] => (string) BlogAuthor
)
[2] => array(1) (
[Account_Manager] => (string) CommentManager
)
)
有没有我误解或忽略的地方?
如果你的 $value
角色已经存在,你必须循环 $contstants
并在你的 $returnHierarchy
中搜索 如果没有则创建新角色
要在数组中搜索,您必须使用递归函数,它将 return 匹配子数组索引引用
// IMPORTANT: it return reference function mae mast start with &
function &searchKeyInArray($key, &$array){
$matchedArrayReffarance = null;
if( !isset($array[$key]) ){
foreach ($array as &$sub){
if(is_array($sub)){
$matchedArrayReffarance = &searchKeyInArray($key, $sub);
}
}
}else{
$matchedArrayReffarance = &$array;
}
return $matchedArrayReffarance;
}
然后简单地使用上面定义的 searchKeyInArray
你可以实现你正在寻找的东西
$returnHierarchy = array();
// This is example, in your case it is: $constants = $reflector->getConstants();
$constants = array(
'Administrator' => "",
'Account_Manager' => "Administrator",
'BlogAuthor' => "Account_Manager",
'CommentManager' => "Account_Manager",
);
foreach ($constants as $key => $value) {
$matchArray = &searchKeyInArray($value, $returnHierarchy);
if( isset($matchArray) ){
$matchArray[$value][$key] = array();
}else{
$returnHierarchy[$key] = array();
}
}
var_dump($returnHierarchy);
$returnHierarchy
的var_dump将是
array(1) {
["Administrator"]=> &array(1) {
["Account_Manager"]=> array(2) {
["BlogAuthor"]=> array(0) { }
["CommentManager"]=> array(0) { }
}
}
}