python 2.7批量解压zip文件到目标目录

Question

我正在尝试遍历压缩文件的文件夹并将它们解压缩到目标目录。我的代码是：

import os
import zipfile

def mass_extract():
    source_directory = raw_input("Where are the zips? ")

    if not os.path.exists(source_directory):
        print "Sorry, that folder doesn't seem to exist."
        source_directory = raw_input("Where are the zips? ")

    target_directory = raw_input("To where do you want to extract the files? ")
    if not os.path.exists(target_directory):
        os.mkdir(target_directory)

    for path, directory, filename in os.walk(source_directory):
        zip_file = zipfile.ZipFile(filename, 'w')
        zipfile.extract(zip_file, target_directory)
        zip_file.close()

    print "Done."

这里有两个错误：

AttributeError: 'module' object has no attribute 'extract'
Exception AttributeError:"'list' object has no attribute 'tell'" in <bound method ZipFile.__del__ of <zipfile.ZipFile object at 0xb701d52c>> ignored

有什么问题吗？

Answer 1

尝试将 zipfile.extract 更改为 zip_file.extractall

编辑：从移动端回来，这里有一些更简洁的代码。我注意到初始代码不会运行因为 'filename' 实际上是该目录的文件列表。此外，将其打开为 write 又名 w 只会覆盖您现有的 zip 文件，您不希望这样。

for path, directory, filenames in os.walk(source_directory):
    for each_file in filenames:
        file_path = os.path.join(path, each_file)
        if os.path.splitext(file_path)[1] == ".zip": # Make sure it's a zip file
            with zipfile.ZipFile(file_path) as zip_file:
                zip_file.extractall(path=target_directory)

Here 是我刚才使用的 zipfile 代码示例。

python 2.7批量解压zip文件到目标目录

python 2.7 mass zip file extraction to target directory

python

zip

os.walk