如何将关键字放入我的代码中？

Question

好吧，那么我该如何编写我的代码，而不是将 1 到 4，我可以只输入一个关键字，如 "Freezing" 或 "Froze" 我如何在我的代码中添加一个关键字搜索器，非常感谢所有帮助，在此先感谢您:)

    def menu():
  print("Welcome to Kierans Phone Troubleshooting program")
  print("Please Enter your name")
  name=input()
  print("Thanks for using Kierans Phone Troubleshooting program "+name +"\n")

def start():
  select = " "
  print("Would you like to start this program? Please enter either y for yes or n for no")
  select=input()
  if select=="y":
    troubleshooter()
  elif select=="n":
    quit
  else:
    print("Invalid please enter again")

def troubleshooter():
  print("""Please choose the problem you are having with your phone (input 1-4):
1) My phone doesn't turn on
2) My phone is freezing
3) The screen is cracked
4) I dropped my phone in water\n""")
  problemselect = int(input())
  if problemselect ==1:
    not_on()
  elif problemselect ==2:
    freezing()
  elif problemselect ==3:
    cracked()
  elif problemselect ==4:
    water()
  start()

def not_on():
  print("Have you plugged in the charger?")
  answer = input()
  if answer =="y":
    print("Charge it with a diffrent charger in a diffrent phone socket. Does it work?")
  else:
    print("Plug it in and leave it for 20 mins, has it come on?")
  answer = input()
  if answer=="y":
    print("Are there any more problems?")
  else:
    print("Restart the troubleshooter or take phone to a specialist\n")
  answer=input()
  if answer =="y":
    print("Restart this program")
  else:
    print("Thank you for using my troubleshooting program!\n")

def freezing():
  print("Charge it with a diffrent charger in a diffrent phone socket")
  answer = input("Are there any more problems?")
  if answer=="y":
    print("Restart the troubleshooter or take phone to a specialist\n")
  else:
    print("Restart this program\n")

def cracked():
  answer =input("Is your device responsive to touch?")
  if answer=="y":
    answer2 = input("Are there any more problems?")
  else:
    print("Take your phone to get the screen replaced")
  if answer2=="y":
    print("Restart the program or take phone to a specialist\n")
  else:
    print("Thank you for using my troubleshooting program!\n")

def water():
  print("Do not charge it and take it to the nearest specialist\n")

menu()
while True:
  start()
  troubleshooter()

Answer 1

您正在寻找 enum

from enum import Enum
class Status(Enum):
    NOT_ON = 1
    FREEZING = 2
    CRACKED = 3
    WATER = 4

然后在你的 if 支票中，你做这样的事情：

if problemselect == Status.NOT_ON:
    ...
elif problemselect == Status.FREEZING:
    ...

Answer 2

由于您希望用户输入 phone 问题的描述，因此您可能需要一个问题列表以及与这些问题相关的关键字。下面的程序展示了如何安排这样一个数据库，以及如何根据用户的输入来搜索它。这个解决方案有更快的替代方案（例如索引数据库），但这个基本实现暂时应该足够了。您将需要提供有关如何解决问题的更多代码和信息，但您对上一个问题的回答应该有助于指导您解决这方面的问题。

#! /usr/bin/env python3

# The following is a database of problem and keywords for those problems.
# Its format should be extended to take into account possible solutions.
PROBLEMS = (('My phone does not turn on.',
             {'power', 'turn', 'on', 'off'}),
            ('My phone is freezing.',
             {'freeze', 'freezing'}),
            ('The screen is cracked.',
             {'cracked', 'crack', 'broke', 'broken', 'screen'}),
            ('I dropped my phone in water.',
             {'water', 'drop', 'dropped'}))


# These are possible answers accepted for yes/no style questions.
POSITIVE = tuple(map(str.casefold, ('yes', 'true', '1')))
NEGATIVE = tuple(map(str.casefold, ('no', 'false', '0')))


def main():
    """Find out what problem is being experienced and provide a solution."""
    description = input('Please describe the problem with your phone: ')
    words = {''.join(filter(str.isalpha, word))
             for word in description.lower().split()}
    for problem, keywords in PROBLEMS:
        if words & keywords:
            print('This may be what you are experiencing:')
            print(problem)
            if get_response('Does this match your problem? '):
                print('The solution to your problem is ...')
                # Provide code that shows how to fix the problem.
                break
    else:
        print('Sorry, but I cannot help you.')


def get_response(query):
    """Ask the user yes/no style questions and return the results."""
    while True:
        answer = input(query).casefold()
        if answer:
            if any(option.startswith(answer) for option in POSITIVE):
                return True
            if any(option.startswith(answer) for option in NEGATIVE):
                return False
        print('Please provide a positive or negative answer.')


if __name__ == '__main__':
    main()

如何将关键字放入我的代码中？

How Can I Put Keywords Into My Code?

python

idioms

parameterization

decomposition

python-3.x