如何在 soaplib 视图文件中获取请求 HTTP headers？

Question

我有用于 web 服务的 soaplib 作为 soap [服务器]，所有请求路由和响应都是 xml url well.but 我无法获取请求 http headers ，如何获取请求 HTTP headers 以呈现视图 class 的某些方法？

like this method :

def redirect_http(self,request):
    return render(request, 'ask/redirect.html', {
        ''' 'question': question,
        'error_message': "You didn't select a choice.", '''
    })

代码项目：

soap.py

'''
documentation in http://soaplib.github.com/soaplib/2_0/
'''
import base64
import soaplib
from soaplib.core import Application
from soaplib.core.model import primitive as soap_types
from soaplib.core.service import DefinitionBase
from soaplib.core.service import rpc as soapmethod
from soaplib.core.server import wsgi
from soaplib.core.model.clazz import ClassModel
from soaplib.core.model.clazz import Array

from django.http import HttpResponse

# the class with actual web methods

# the class which acts as a wrapper between soaplib WSGI functionality and Django
class DjangoSoapApp(wsgi.Application):
    def __call__(self, request):
        # wrap the soaplib response into a Django response object
        django_response = HttpResponse()
        def start_response(status, headers):
            status, reason = status.split(' ', 1)
            django_response.status_code = int(status)
            for header, value in headers:
                django_response[header] = value
        response = super(DjangoSoapApp, self).__call__(request.META, start_response)
        django_response.content = '\n'.join(response)
        return django_response

class SoapView(DefinitionBase):
    @classmethod
    def as_view(cls):
        soap_application = Application([cls], __name__)
        return DjangoSoapApp(soap_application)


# the view to use in urls.py
#my_soap_service = DjangoSoapApp([MySOAPService], __name__)

views.py

from soap import SoapView
from soap import soapmethod
from soap import soap_types, Array
class MySoapService(SoapView):
    __tns__ = '[url]http://localhost:8989/api/soap/verify.wsdl[/url]'
    @soapmethod(soap_types.String, soap_types.Integer, returns=soap_types.String)
    def request_verify(self, q, id, uri):
        #Some Code
        return 'some return'
my_soap_service = MySoapService.as_view()

urls.py

from django.conf.urls import patterns, include, url
from django.views.generic import RedirectView
import views

# Main URL Patterns
urlpatterns = [
  url(r'^verify', views.my_soap_service),
  url(r'^verify.wsdl', views.my_soap_service),
]

Answer 1

问题已解决：更改方法请求（用于生成 html 并获取 http header 大多数观察协议 HTTP 和结构），因此请求和响应 html 内容应发送 http请求并获取所有 header 生成的

如何在 soaplib 视图文件中获取请求 HTTP headers？

how to get request HTTP headers in soaplib views file?

python

httprequest

soaplib