我有一个数组数组并将其传递给 scala 中的函数但出现错误

Question

我需要实现距离搜索code.My CSV 中的输入如下。

Proprty_ID,  lat,    lon
123,    33.84,  -118.39
234,    35.89,  -119.48
345,    35.34,  -119.39

我有一个 haversine 公式，它采用 2 个坐标 (lat1, lon1), (lat2, lon2) 和 return 距离。假设：

val Distance: Double = haversine(x1:Double, x2:Double, y1:Double, y2:Double)

我需要找出每个属性彼此之间的距离。所以输出看起来像这样。

Property_ID1, Property_ID2, distance
123,123,0
123,234,0.1
123,345,0.6
234,234,0
234,123,0.1
234,345,0.7
345,345,0
345,123,0.6
345,234,0.7

如何在 Scala 中实现它？

import math._

object Haversine {
   val R = 6372.8  //radius in km

   def haversine(lat1:Double, lon1:Double, lat2:Double, lon2:Double)={
      val dLat=(lat2 - lat1).toRadians
      val dLon=(lon2 - lon1).toRadians

      val a = pow(sin(dLat/2),2) + pow(sin(dLon/2),2) * cos(lat1.toRadians) * cos(lat2.toRadians)
      val c = 2 * asin(sqrt(a))
      R * c
   }

   def main(args: Array[String]): Unit = {
      println(haversine(36.12, -86.67, 33.94, -118.40))
  }
}

class SimpleCSVHeader(header:Array[String]) extends Serializable {
  val index = header.zipWithIndex.toMap
  def apply(array:Array[String], key:String):String = array(index(key))
}

val lat1=33.84
val lon1=-118.39
val csv = sc.textFile("file.csv") 
val data = csv.map(line => line.split(",").map(elem => elem.trim)) 
val header = new SimpleCSVHeader(data.take(1)(0)) // we build our header with the first line
val rows = data.filter(line => header(line,"lat") != "lat") // filter the header out

// I will do the looping for all properties here but I am trying to get the map function right for one property at least
val distances = rows.map(x => haversine(x.take(1)(0).toDouble,x.take(1)(1).toDouble, lat1,lon1)`

现在这应该给我所有属性与 (lat1, lon1) 的距离。我知道这是不对的，但我无法从这里思考。

Answer 1

我会尝试将其分解为多个步骤。给出的数据如下：

  val rows = List(Array("123", "33.84", "-118.39"),
                  Array("234", "35.89", "-119.48"),
                  Array("345", "35.34", "-119.39"))

首先转换类型：

  val typed = rows.map{ case Array(id, lat, lon) => (id, lat.toDouble, lon.toDouble)}

然后生成组合：

  val combos = for {
    a <- typed
    b <- typed
  } yield (a,b)

然后为每个组合生成一个输出行：

  combos.map{ case ((id1, lat1, lon1), (id2, lat2, lon2)) 
     => id1 + "," + id2 + "," + haversine(lat1, lon1, lat2, lon2)} foreach println

我有一个数组数组并将其传递给 scala 中的函数但出现错误

I have an array of array and passing it to a function in scala but getting errors

scala

multidimensional-array

haversine