R - 将数据帧合并为 table，用斜杠 ("/") 分隔值

Question

我正在使用如下所示的数据框：

tbl45 <- structure(list(`2010's` = c(0.48, 1.45, 33.33, 25.6, 32.37, 6.76
), `2020's` = c(0.48, 0.97, 31.88, 36.71, 28.5, 1.45), `2030's` = c(0.48, 
1.93, 27.54, 34.3, 33.33, 2.42), `2040's` = c(0.48, 1.93, 33.33, 
26.57, 28.5, 9.18), `2050's` = c(0.48, 1.93, 33.33, 26.09, 32.85, 
5.31), `2060's` = c(0.48, 3.38, 25.6, 32.37, 36.23, 1.93), `2070's` = c(0.48, 
1.93, 33.82, 28.99, 31.4, 3.38), `2080's` = c(0.48, 2.42, 34.3, 
31.4, 28.99, 2.42), `2090's` = c(0.48, 2.42, 31.4, 33.33, 29.95, 
2.42)), .Names = c("2010's", "2020's", "2030's", "2040's", "2050's", 
"2060's", "2070's", "2080's", "2090's"), row.names = c("[0,100]", 
"(100,200]", "(200,300]", "(300,400]", "(400,500]", "(500,600]"
), class = "data.frame")

tbl85 <- structure(list(`2010's` = c(0.48, 1.45, 31.4, 30.43, 34.78, 1.45
), `2020's` = c(0.48, 1.45, 36.23, 29.95, 30.43, 1.45), `2030's` = c(0.48, 
1.93, 32.37, 28.02, 34.3, 2.9), `2040's` = c(0.48, 2.9, 30.43, 
33.33, 31.4, 1.45), `2050's` = c(0.48, 2.9, 32.85, 30.43, 29.47, 
3.86), `2060's` = c(0.48, 4.83, 33.33, 30.43, 26.57, 4.35), `2070's` = c(0.48, 
5.8, 31.88, 36.23, 24.15, 1.45), `2080's` = c(0.48, 5.8, 35.27, 
33.82, 23.19, 1.45), `2090's` = c(1.45, 8.21, 38.16, 32.85, 17.87, 
1.45)), .Names = c("2010's", "2020's", "2030's", "2040's", "2050's", 
"2060's", "2070's", "2080's", "2090's"), row.names = c("[0,100]", 
"(100,200]", "(200,300]", "(300,400]", "(400,500]", "(500,600]"
), class = "data.frame")

我想将它们组合成一个 table（或数据框），值之间用斜杠（“/”）或括号分隔。然后我将它保存为.xls文件并将table复制到word.

最终结果将是这样的（为了简单起见，我只显示了第一列）：

               2010's 
[0,100]     0.48 / 0.48 
(100,200]   1.45 / 1.45
(200,300]  33.33 / 31.40
(300,400]  25.60 / 30.43
(400,500]  32.37 / 34.78
(500,600]   6.76 / 1.45

我如何使用 R 实现这一点？

Answer 1

试试这个：

res <- mapply(function(x,y) paste(x,y, sep = "/"), tbl45, tbl85)
rownames(res) <- rownames(tbl45)
res
          2010's        2020's        2030's        2040's        2050's        2060's       
[0,100]   "0.48/0.48"   "0.48/0.48"   "0.48/0.48"   "0.48/0.48"   "0.48/0.48"   "0.48/0.48"  
(100,200] "1.45/1.45"   "0.97/1.45"   "1.93/1.93"   "1.93/2.9"    "1.93/2.9"    "3.38/4.83"  
(200,300] "33.33/31.4"  "31.88/36.23" "27.54/32.37" "33.33/30.43" "33.33/32.85" "25.6/33.33" 
(300,400] "25.6/30.43"  "36.71/29.95" "34.3/28.02"  "26.57/33.33" "26.09/30.43" "32.37/30.43"
(400,500] "32.37/34.78" "28.5/30.43"  "33.33/34.3"  "28.5/31.4"   "32.85/29.47" "36.23/26.57"
(500,600] "6.76/1.45"   "1.45/1.45"   "2.42/2.9"    "9.18/1.45"   "5.31/3.86"   "1.93/4.35"  
          2070's        2080's        2090's       
[0,100]   "0.48/0.48"   "0.48/0.48"   "0.48/1.45"  
(100,200] "1.93/5.8"    "2.42/5.8"    "2.42/8.21"  
(200,300] "33.82/31.88" "34.3/35.27"  "31.4/38.16" 
(300,400] "28.99/36.23" "31.4/33.82"  "33.33/32.85"
(400,500] "31.4/24.15"  "28.99/23.19" "29.95/17.87"
(500,600] "3.38/1.45"   "2.42/1.45"   "2.42/1.45"

Answer 2

我们可以通过 unlist 两个数据集然后 paste

来做到这一点

res <- tbl45
res[] <- paste(unlist(tbl45), unlist(tbl85), sep='/')
res
#            2010's      2020's      2030's      2040's      2050's
#[0,100]     0.48/0.48   0.48/0.48   0.48/0.48   0.48/0.48   0.48/0.48
#(100,200]   1.45/1.45   0.97/1.45   1.93/1.93    1.93/2.9    1.93/2.9
#(200,300]  33.33/31.4 31.88/36.23 27.54/32.37 33.33/30.43 33.33/32.85
#(300,400]  25.6/30.43 36.71/29.95  34.3/28.02 26.57/33.33 26.09/30.43
#(400,500] 32.37/34.78  28.5/30.43  33.33/34.3   28.5/31.4 32.85/29.47
#(500,600]   6.76/1.45   1.45/1.45    2.42/2.9   9.18/1.45   5.31/3.86
#               2060's      2070's      2080's      2090's
#[0,100]     0.48/0.48   0.48/0.48   0.48/0.48   0.48/1.45
#(100,200]   3.38/4.83    1.93/5.8    2.42/5.8   2.42/8.21
#(200,300]  25.6/33.33 33.82/31.88  34.3/35.27  31.4/38.16
#(300,400] 32.37/30.43 28.99/36.23  31.4/33.82 33.33/32.85
#(400,500] 36.23/26.57  31.4/24.15 28.99/23.19 29.95/17.87
#(500,600]   1.93/4.35   3.38/1.45   2.42/1.45   2.42/1.45

R - 将数据帧合并为 table，用斜杠 ("/") 分隔值

R - Combine data frames to a table, separating values with a slash ("/")

merge

r

separator

dataframe