如何使用 compareTo 方法比较两个字符串和 return 字典顺序的结果？

Question

我正在尝试使用 compareTo 方法来比较两个不同的名称。在运行第一次尝试后，程序立即终止，没有 return 任何东西。如何修改此 compareTo 方法以比较名称（名称 n 和名称 n2）和 return 结果（-1、1 或 0）？并且显然可以添加打印语句来显示（等于、之前或之后）以进行比较。感谢您的帮助。

//First attempt
public class Name implements Comparable<Name> {

    private String Name;

    public Name(String string) {
        // TODO Auto-generated constructor stub
    }
    public String getName() {
        return Name;
    }
    public int compareTo(Name other) {

        if (getName().compareTo(other.getName()) < 0) {
            return -1;
        } else if (getName().compareTo(other.getName()) > 0) {
            return 1;
        } else if (getName().equals(other.getName())) {
            return 0;
        }
        return getName().compareTo(other.getName());
    }
    public static void main(String[] args) {
        Name n = new Name("jennifer");
        n.getName();
        Name n2 = new Name("paul");
        n2.getName();
    }
}




//second attempt
    public class Name implements Comparable<String> {

        private String Name;

        public String getName() {
            return Name;
        }
        public int compareTo(String other) {

            if (getName().compareTo(other.getName()) < 0) {
                return -1;
            } else if (getName().compareTo(other.getName()) > 0) {
                return 1;
            } else if (getName().equals(other.getName())) {
                return 0;
            }
            return getName().compareTo(other.getName());

        }
        public static void main(String[] args) {
            String Name = new String("jennifer");

            String other = new String("paul");
        }
    }

Answer 1

public class Name implements Comparable<Name> {

    private String name;

    public Name(String name) {
        this.name=name;
    }
    public String getName() {
        return name;
    }
    public int compareTo(Name other) {

        if (getName().compareTo(other.getName()) < 0) {
            return -1;
        } else if (getName().compareTo(other.getName()) > 0) {
            return 1;
        } else if (getName().equals(other.getName())) {
            return 0;
        }
        return getName().compareTo(other.getName());
    }
    public static void main(String[] args) {
        Name n = new Name("jennifer");
        n.getName();
        Name n2 = new Name("paul");
        n2.getName();
       System.out.println(n.getName());
      System.out.println(n2.getName());
       System.out.println(n2.compareTo(n));

    }
}

输出：詹妮弗保罗 1

Answer 2

//First attempt
public class Name {

    public static void main(String[] args) {
        String n = new String("jennifer");
        String n2 = new String("paul");
        if (n.compareTo(n2) < 0) {
            System.out.println(n +" is before than " +n2);
        } else if (n.compareTo(n2) > 0) {
            System.out.println(n +" is after than " +n2);
        } else if (n.compareTo(n2) == 0) {
            System.out.println(n +" is equals to " +n);
        }
    }   
}

输出：

jennifer is before than paul

顺便说一下，check this out 因为每种编程语言都有自己的一套规则和约定，Java 中的变量是这样的：

If the name you choose consists of only one word, spell that word in all lowercase letters. If it consists of more than one word, capitalize the first letter of each subsequent word.

如何使用 compareTo 方法比较两个字符串和 return 字典顺序的结果？

How can I compare two strings and return the lexicographical ordered result using the compareTo method?

java

string

getter

compare

comparable