有没有办法 create/modify 在 python 中即时运行
Is there a way to create/modify function on the fly in python
我尝试用 python 模拟键盘,但我不知道如何处理多个键盘按钮按下。下面的代码在同时按下 1 或 2 个键的情况下工作得很好 (fe 'ctrl + c'):
if '+' in current_arg:
current_arg = current_arg.split('+')
current_arg[0] = current_arg[0].strip()
current_arg[1] = current_arg[1].strip()
SendInput(Keyboard(globals()["VK_%s" % current_arg[0].upper()]),
Keyboard(globals()["VK_%s" % current_arg[1].upper()]))
time.sleep(input_time_down())
if len(last_arg) > 1 and type(last_arg) == list:
SendInput(Keyboard(globals()["VK_%s" % last_arg[0].upper()], KEYEVENTF_KEYUP),
Keyboard(globals()["VK_%s" % last_arg[1].upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
else:
SendInput(Keyboard(globals()["VK_%s" % last_arg.upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
但是如果同时按下了3个或更多的按钮呢?最优雅的方法是什么?我可以只添加 if '+' count == 2,if '+' count == 3 等等,但必须有更好的方法来做到这一点。我希望我的函数能够适应参数的数量。
例如:
keyboard_sim('ctrl + shift + esc'):
if '+' in current_arg:
current_arg = current_arg.split('+')
current_arg[0] = current_arg[0].strip()
### function adds another current_arg for each argument
current_arg[1] = current_arg[1].strip()
current_arg[2] = current_arg[2].strip()
SendInput(Keyboard(globals()["VK_%s" % current_arg[0].upper()]),
### function adds another Keyboard for each argument
Keyboard(globals()["VK_%s" % current_arg[1].upper()]))
Keyboard(globals()["VK_%s" % current_arg[2].upper()]))
time.sleep(input_time_down())
if len(last_arg) > 1 and type(last_arg) == list:
### function adds another Keyboard KEYEVENTF for each argument
SendInput(Keyboard(globals()["VK_%s" % last_arg[0].upper()], KEYEVENTF_KEYUP),
Keyboard(globals()["VK_%s" % last_arg[1].upper()], KEYEVENTF_KEYUP))
Keyboard(globals()["VK_%s" % last_arg[2].upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
else:
### this is added so I won't get error if there is single key pressed
SendInput(Keyboard(globals()["VK_%s" % last_arg.upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
我不熟悉您正在使用的 SendInput/Keyboard 东西,所以我假设它们是您自定义和编写的。
假设 SendInput
的定义类似于 def SendInput(*args)
(如@JETM 所建议)并且 last_arg 实际上应该是 current_arg,您应该可以调用它像这样:
arglist = current_arg.split('+')
# This will create a list of Keyboard objects
keys = [KeyBoard(globals()["VK_%s" % key.upper()]) for key in arglist]
# *keys splits the list of Keyboard objects so that SendInput receives
# one entry in it's argument list for each Keyboard object in keys
SendInput(*keys)
使用此方法,在 SendInput 中,args 变量将是一个列表,每个键都有一个键盘对象。
我尝试用 python 模拟键盘,但我不知道如何处理多个键盘按钮按下。下面的代码在同时按下 1 或 2 个键的情况下工作得很好 (fe 'ctrl + c'):
if '+' in current_arg:
current_arg = current_arg.split('+')
current_arg[0] = current_arg[0].strip()
current_arg[1] = current_arg[1].strip()
SendInput(Keyboard(globals()["VK_%s" % current_arg[0].upper()]),
Keyboard(globals()["VK_%s" % current_arg[1].upper()]))
time.sleep(input_time_down())
if len(last_arg) > 1 and type(last_arg) == list:
SendInput(Keyboard(globals()["VK_%s" % last_arg[0].upper()], KEYEVENTF_KEYUP),
Keyboard(globals()["VK_%s" % last_arg[1].upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
else:
SendInput(Keyboard(globals()["VK_%s" % last_arg.upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
但是如果同时按下了3个或更多的按钮呢?最优雅的方法是什么?我可以只添加 if '+' count == 2,if '+' count == 3 等等,但必须有更好的方法来做到这一点。我希望我的函数能够适应参数的数量。
例如:
keyboard_sim('ctrl + shift + esc'):
if '+' in current_arg:
current_arg = current_arg.split('+')
current_arg[0] = current_arg[0].strip()
### function adds another current_arg for each argument
current_arg[1] = current_arg[1].strip()
current_arg[2] = current_arg[2].strip()
SendInput(Keyboard(globals()["VK_%s" % current_arg[0].upper()]),
### function adds another Keyboard for each argument
Keyboard(globals()["VK_%s" % current_arg[1].upper()]))
Keyboard(globals()["VK_%s" % current_arg[2].upper()]))
time.sleep(input_time_down())
if len(last_arg) > 1 and type(last_arg) == list:
### function adds another Keyboard KEYEVENTF for each argument
SendInput(Keyboard(globals()["VK_%s" % last_arg[0].upper()], KEYEVENTF_KEYUP),
Keyboard(globals()["VK_%s" % last_arg[1].upper()], KEYEVENTF_KEYUP))
Keyboard(globals()["VK_%s" % last_arg[2].upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
else:
### this is added so I won't get error if there is single key pressed
SendInput(Keyboard(globals()["VK_%s" % last_arg.upper()], KEYEVENTF_KEYUP))
time.sleep(input_time_down())
我不熟悉您正在使用的 SendInput/Keyboard 东西,所以我假设它们是您自定义和编写的。
假设 SendInput
的定义类似于 def SendInput(*args)
(如@JETM 所建议)并且 last_arg 实际上应该是 current_arg,您应该可以调用它像这样:
arglist = current_arg.split('+')
# This will create a list of Keyboard objects
keys = [KeyBoard(globals()["VK_%s" % key.upper()]) for key in arglist]
# *keys splits the list of Keyboard objects so that SendInput receives
# one entry in it's argument list for each Keyboard object in keys
SendInput(*keys)
使用此方法,在 SendInput 中,args 变量将是一个列表,每个键都有一个键盘对象。