IoC StructureMap 解析命名实例

Question

对于以下代码，我将如何根据名称解析？

public interface IService
{}

public class ServiceA : IService
{}

public class ServiceB : IService
{}

public class ClassA
{
    public IService service { get; set; }

    public ClassA(IService service)
    {
        this.service = service;
    }
}

public class ClassB
{
    public IService service { get; set; }

    public ClassB(IService service)
    {
        this.service = service;
    }
}

注册表：

public class MyRegistry : Registry
{
    public MyRegistry()
    {
        For<IService>().Add<ServiceA>().Ctor<IService>().Is(i => i.GetInstance<IService>("ServiceA")); // error
    }
}

用法：

container = new Container(new MyRegistry());
var test = container.GetInstance<ClassA>();

问题：

对于 ClassA IService => 应该产生 ServiceA
For ClassB IService => 应该产生 ServiceB
另外，有没有办法在构造函数中使用属性来指定特定类型的具体实现？（所以配置里不用指定？）

Answer 1

我们已经创建了自己的 RegistrationConvention（注意这个实现将每个插件系列注册为 Singleton）：

    public class SingletonConvention<TPluginFamily> : IRegistrationConvention
{
    public void Process(Type type, Registry registry)
    {
        if (!type.IsConcrete() || !type.CanBeCreated() || !type.AllInterfaces().Contains(typeof(TPluginFamily)))
            return;

        registry.For(typeof(TPluginFamily)).Singleton().Use(type).Named(type.Name);
    }
}

然后在我们的注册表中（下面未测试）：

        Scan(y =>
        {
            y.With(new SingletonConvention<IService>());
            y.Assembly(Assembly.GetExecutingAssembly().FullName);
        });

        For<ClassA>()
            .Use<ClassA>()
            .Ctor<IService >("service").Is("service",x =>
            {
                var service = x.GetInstance<IService>().Named("ServiceA");

                return service;
            })

Answer 2

我已经像这样工作了> @ozczcho 的回答很有帮助。谢谢

    For<ClassA>().Use<ClassA>().Ctor<IService>("service").Is<ServiceA>();
    For<ClassB>().Use<ClassB>().Ctor<IService>("service").Is<ServiceB>();

IoC StructureMap 解析命名实例

IoC StructureMap resolve named instance

c#

.net

structuremap