使用 AngularJS 中的 ngOptions 隐藏其他列表中的选定选项
Hide selected option in other list using ngOptions in AngularJS
希望有人能帮助解决这个挑战。
我在两个单独的下拉列表中使用了 1 个机场数组。
<select data-ng-model="flightData.origin" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="origin"></select>
和
<select data-ng-model="flightData.destination" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="destination"></select>
这两个列表显然具有相同的选项。我想做的是,当您 select 例如 "Sydney"
在原点时,从目标下拉列表中删除 "Sydney"
。
作为参考,这是机场数据的示例。
this.airports = [{
code: "TSV",
label: "Townsville",
}, {
code: "PER",
label: "Perth",
}, {
code: "BNE",
label: "Brisbane",
}, {
code: "MEL",
label: "Melbourne",
}, {
code: "KGI",
label: "Kalgoorlie",
}, {
code: "SYD",
label: "Sydney",
},{
code: "LAX",
label: "Los Angeles",
}, {
code: "JFK",
label: "New York",
}, {
code: "DEL",
label: "New Dehli",
}];
我知道我很可能需要两个单独的数组(1 个用于起点,1 个用于目的地),只是不确定如何处理它。
谢谢!
使用ng-change
并且您还需要两个列表。
<select data-ng-model="flightData.airports_origin" ng-change="changeOrigin()" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="origin"></select>
<select data-ng-model="flightData.airports_destination" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="origin"></select>
在您的控制器中,注入 filterFilter
,然后在可用目的地机场列表中搜索所选机场并将其删除。
// in your controller
$scope.airports_origin = angular.copy(this.airport);
$scope.airports_destination = angular.copy(this.airport);
$scope.changeOrigin = function(){
var selected_origin = flightData.origin;
var destination_airport = filterFilter(this.airports_destination,{'code':selected_origin.code})[0];
$scope.airports_destination.splice($scope.airports_destination.indexOf(destination_airport),1);
}
希望有人能帮助解决这个挑战。
我在两个单独的下拉列表中使用了 1 个机场数组。
<select data-ng-model="flightData.origin" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="origin"></select>
和
<select data-ng-model="flightData.destination" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="destination"></select>
这两个列表显然具有相同的选项。我想做的是,当您 select 例如 "Sydney"
在原点时,从目标下拉列表中删除 "Sydney"
。
作为参考,这是机场数据的示例。
this.airports = [{
code: "TSV",
label: "Townsville",
}, {
code: "PER",
label: "Perth",
}, {
code: "BNE",
label: "Brisbane",
}, {
code: "MEL",
label: "Melbourne",
}, {
code: "KGI",
label: "Kalgoorlie",
}, {
code: "SYD",
label: "Sydney",
},{
code: "LAX",
label: "Los Angeles",
}, {
code: "JFK",
label: "New York",
}, {
code: "DEL",
label: "New Dehli",
}];
我知道我很可能需要两个单独的数组(1 个用于起点,1 个用于目的地),只是不确定如何处理它。
谢谢!
使用ng-change
并且您还需要两个列表。
<select data-ng-model="flightData.airports_origin" ng-change="changeOrigin()" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="origin"></select>
<select data-ng-model="flightData.airports_destination" data-ng-options="airport.code as airport.label for airport in flightData.airports" name="origin"></select>
在您的控制器中,注入 filterFilter
,然后在可用目的地机场列表中搜索所选机场并将其删除。
// in your controller
$scope.airports_origin = angular.copy(this.airport);
$scope.airports_destination = angular.copy(this.airport);
$scope.changeOrigin = function(){
var selected_origin = flightData.origin;
var destination_airport = filterFilter(this.airports_destination,{'code':selected_origin.code})[0];
$scope.airports_destination.splice($scope.airports_destination.indexOf(destination_airport),1);
}