继续后如何return到循环的特定部分？

Question

我正在学习使用类。我已将异常构建到我定义的方法之一 setBirthday 中。它确保输入适合真正的生日输出。这部分代码无法正常工作。

    def setBirthday(you):
    while True:
        #get numeric birth month
        try:
            m = int(raw_input("What is your birth month?"))
        except ValueError:
            print "Enter an integer, please try again."
            continue
        if m <= 0:
            print "Enter a number between 1-12, please try again."
            continue
        elif m >= 13:
            print "Enter a number between 1-12, please try again."
            continue
      #get birth date
        try:
            d = int(raw_input("What day were you born that month?"))
        except ValueError:
            print "Enter an integer, please try again."
            continue        
        if d <= 0:
            print "Enter a number between 1-31, please try again."
            continue
        elif d >= 32:
            print "Enter a number between 1-31, please try again."
            continue
        #get birth year
        try:
            y = int(raw_input("What year were you born?"))
        except ValueError:
            print "Enter an integer, please try again."
            continue        
        if y <= 0:
            print "Enter a number greater than zero, please try again."
            continue
        else:
            break
    you.bday = datetime(y, m, d)
    age = str(m) + "/" + str(d) + "/" + str(y)
    print "Your birthday is " + (age)

因为它现在运行，如果有人输入不希望输入的日期 (d) 或出生年份 (y)，'continue' 再次重新启动整个循环：询问出生月份、日期，年。我想让它在出错的地方（日期或年份）继续，而不是再次询问用户之前的良好输入以达到这一点。如有任何帮助，我们将不胜感激。

Answer 1

while True:
    #get numeric birth month
    try:
        m = int(raw_input("What is your birth month?"))
    except ValueError:
        print "Enter an integer, please try again."
        continue
    if m <= 0 or m >= 13:
        print "Enter a number between 1-12, please try again."
    else:
        break

然后相同的循环用于日，第三个循环用于年。

继续后如何return到循环的特定部分？

How to return to a particular part of a loop after continue?

python-2.7

try-catch

continue