嵌套循环显示 25 个字符的行 c++

Question

您好，我在使用嵌套循环输出用户选择的 25 个字符的行时遇到了一些问题。每行应该有 25 个字符，用户输入要打印的行数。

另外，每一行都需要比上一行多一个制表符。

目前我只能让程序输出一行字符，否则它会显示选中的一个字符的25行。

请帮忙。欢迎任何意见。

int lines=0, count=0, amount=0, symbol, i=0, j=0;

do {
    cout << "\nEnter number of lines to print: ";
    cin >> lines;
    if (lines < 5 ) {
        cout << "Please enter an integer greater than 5." << endl;
        system("pause");            
    }
    else if (lines >= 5) {
        cout << "\nEnter the number corresponding to the character you would like to display: ";
        cout << "\n 1. * \n 2. $ \n 3. # \n 4. ! \n 5. & \n ";
        cin >> symbol;

        for (i = 1; i <= 25; i++) {
            cout << symbol << " " ;
            count++;
            for (j = 1; j <= lines; j++) {
                cout << "" << endl;
            }
        }  
    }
} while (1);

Answer 1

你的嵌套循环方式不对。

尝试：

// Iterate parent loop line by line
for(j=1; j<=lines; j++){
    // Add tabs according to the line number
    for(int k=1; k<j; k++){
        cout << "\t";
    }

    // Print symbol 25 times each line
    for(i=1; i<=25; i++){
        cout << symbol << " ";
    }
    cout << endl;
}

嵌套循环显示 25 个字符的行 c++

Nested loops to display rows of 25 characters c++

c++

for-loop

nested-loops