两个日期之间的周数
Week numbers between two dates
我正在尝试获取两个日期之间的周数。
例如,在日期 01/01/2016 和 29/02/2016 之间我应该
S01 S02 S03 S04 S05 S06 S07 S08
可能吗?怎么做到的?
SELECT 'S' || LPAD( LEVEL, 2, '0' )
FROM DUAL
CONNECT BY DATE '2016-01-01' + ( LEVEL - 1 ) * 7 <= DATE '2016-02-29';
输出:
'S'||LPAD(LEVEL,2,'0')
----------------------
S01
S02
S03
S04
S05
S06
S07
S08
S09
更新 - 有月份和日期:
注意:更改了边界以突出显示周数和序号之间的差异。
WITH bounds AS (
SELECT DATE '2016-03-01' AS lower_bound,
DATE '2016-04-30' AS upper_bound
FROM DUAL
),
weeks AS (
SELECT LEVEL AS id,
lower_bound + (LEVEL - 1) * 7 AS week_date
FROM bounds
CONNECT BY lower_bound + (LEVEL - 1) * 7 <= upper_bound
)
SELECT 'S' || LPAD( id, 2, '0' ) AS id,
'W' || TO_CHAR( week_date, 'WW' ) AS week,
'M' || TO_CHAR( week_date, 'MM' ) AS month,
week_date
FROM weeks;
输出:
ID WEEK MONTH WEEK_DATE
--- ---- ----- ---------
S01 W09 M03 01-MAR-16
S02 W10 M03 08-MAR-16
S03 W11 M03 15-MAR-16
S04 W12 M03 22-MAR-16
S05 W13 M03 29-MAR-16
S06 W14 M04 05-APR-16
S07 W15 M04 12-APR-16
S08 W16 M04 19-APR-16
S09 W17 M04 26-APR-16
如果您想要日历周数,那么您可以对 MTO 的回答使用类似的分层方法:
select distinct 'S' || to_char(date '2016-01-01' + level -1, 'WW') as week_num
from dual
connect by level <= date '2016-02-29' - date '2016-01-01'
order by week_num;
WEE
---
S01
S02
S03
S04
S05
S06
S07
S08
S09
如果您想要 ISO 周,则使用 IW 而不是 WW,但这会使第一周成为 S53(从去年开始)。
我正在尝试获取两个日期之间的周数。
例如,在日期 01/01/2016 和 29/02/2016 之间我应该
S01 S02 S03 S04 S05 S06 S07 S08
可能吗?怎么做到的?
SELECT 'S' || LPAD( LEVEL, 2, '0' )
FROM DUAL
CONNECT BY DATE '2016-01-01' + ( LEVEL - 1 ) * 7 <= DATE '2016-02-29';
输出:
'S'||LPAD(LEVEL,2,'0')
----------------------
S01
S02
S03
S04
S05
S06
S07
S08
S09
更新 - 有月份和日期:
注意:更改了边界以突出显示周数和序号之间的差异。
WITH bounds AS (
SELECT DATE '2016-03-01' AS lower_bound,
DATE '2016-04-30' AS upper_bound
FROM DUAL
),
weeks AS (
SELECT LEVEL AS id,
lower_bound + (LEVEL - 1) * 7 AS week_date
FROM bounds
CONNECT BY lower_bound + (LEVEL - 1) * 7 <= upper_bound
)
SELECT 'S' || LPAD( id, 2, '0' ) AS id,
'W' || TO_CHAR( week_date, 'WW' ) AS week,
'M' || TO_CHAR( week_date, 'MM' ) AS month,
week_date
FROM weeks;
输出:
ID WEEK MONTH WEEK_DATE
--- ---- ----- ---------
S01 W09 M03 01-MAR-16
S02 W10 M03 08-MAR-16
S03 W11 M03 15-MAR-16
S04 W12 M03 22-MAR-16
S05 W13 M03 29-MAR-16
S06 W14 M04 05-APR-16
S07 W15 M04 12-APR-16
S08 W16 M04 19-APR-16
S09 W17 M04 26-APR-16
如果您想要日历周数,那么您可以对 MTO 的回答使用类似的分层方法:
select distinct 'S' || to_char(date '2016-01-01' + level -1, 'WW') as week_num
from dual
connect by level <= date '2016-02-29' - date '2016-01-01'
order by week_num;
WEE
---
S01
S02
S03
S04
S05
S06
S07
S08
S09
如果您想要 ISO 周,则使用 IW 而不是 WW,但这会使第一周成为 S53(从去年开始)。