'There is an error in XML document (30, 10)' 从 XML 元素类型返回差异类型时出错

Question

我有一个 XML 文件。我想将它映射到一个对象。 xml 元素之一是字符串，我想将此字符串转换为属性集合部分中枚举的 int 值。然后 return 这个 int 值，但是当文件 reader 想要将我的 XML 文件反序列化为对象时，我得到运行时错误，显示 "There is an error in XML document (30, 10)".

private int processCodeInt;
    [XmlElement("ProcessCode")]
    public int ProcessCode
    {
        get { return this.processCodeInt; }
        set
        {
            var temp = typeof(Common.Transaction.Definition_Transaction.Def_TrxType_Detail)
                .GetMembers().Where(i => i.MemberType == MemberTypes.Field).ToList();
            this.processCodeInt = Convert.ToInt32(temp.Where(u => u.Name == value.ToString()).FirstOrDefault().ToString());
        }
    }

谢谢大家

下面我留下我的代码：

映射类:

[XmlRoot("Model")]
    public class Model
    {
        [XmlElement("Transaction")]
        public List<Transaction> Transactions;
    }
    public class Transaction
    {
        [XmlElement("Message")]
        public List<Message> Messages;
    }
    public class Message
    {
        [XmlElement("In")]
        public MessageType In { get; set; }
        [XmlElement("Out")]
        public MessageType Out { get; set; }
    }
    public class MessageType
    {
        [XmlElement("ChannelType")]
        public int ChannelType { get; set; }
        [XmlElement("TransactionType")]
        public int TransactionType { get; set; }
        private int processCodeInt;
        [XmlElement("ProcessCode")]
        public int ProcessCode
        {
            get { return this.processCodeInt; }
            set
            {
                var temp = typeof(Common.Transaction.Definition_Transaction.Def_TrxType_Detail)
                    .GetMembers().Where(i => i.MemberType == MemberTypes.Field).ToList();
                temp.RemoveAt(0);
                MemberInfo[] processCodeMemberInfos = temp.ToArray();
                this.processCodeInt = Convert.ToInt32(processCodeMemberInfos.Where(u => u.Name == value.ToString()).FirstOrDefault().ToString());

            }
        }
        [XmlElement("IsExpired")]
        public bool IsExpired { get; set; }
    }

我的XML文件：

<?xml version="1.0" encoding="utf-8" ?>
<Model>
  <Transaction>
    <Message>
      <In>
        <ChannelType>0</ChannelType>
        <TransactionType>1</TransactionType>
        <ProcessCode>Balance</ProcessCode>
        <IsExpired>0</IsExpired>
      </In>
      <Out>
        <ChannelType>1</ChannelType>
        <TransactionType>1</TransactionType>
        <ProcessCode>Balance</ProcessCode>
        <IsExpired>0</IsExpired>
      </Out>
    </Message>
  </Transaction>
</Model>

映射代码：

var TransactionModelsFile = new System.IO.StreamReader(System.IO.Path.GetDirectoryName(Assembly.GetEntryAssembly().Location)
            +@"/TransactionModels.xml");
            System.Xml.Serialization.XmlSerializer reader =
            new System.Xml.Serialization.XmlSerializer(typeof(Model));
            overview = (Model)reader.Deserialize(TransactionModelsFile);
            TransactionModelsFile.Close();

Answer 1

如您所见，我只是添加了 Enum 而不是字符串，因为 Balance 不是 int 字段的有效值。但是如果你想把它存储为整数，那么我在这种情况下使用支持字段。

class Program
{
    static void Main(string[] args)
    {
        var ser = new XmlSerializer(typeof(Model));
        using (var fs = new FileStream("source.xml", FileMode.Open))
        {
            var obj = (Model) ser.Deserialize(fs);
            Console.WriteLine(obj.Transactions[0].Messages[0].In.ProcessCode);
        }
    }
}


public class Model
{
    [XmlElement("Transaction")]
    public List<Transaction> Transactions;
}
public class Transaction
{
    [XmlElement("Message")]
    public List<Message> Messages;
}
public class Message
{
    public MessageType In { get; set; }
    public MessageType Out { get; set; }
}

public class MessageType
{
    public int ChannelType { get; set; }
    public int TransactionType { get; set; }
    private int processCodeInt;

    public ProcessCode ProcessCode
    {
        get { return (ProcessCode) processCodeInt; }
        set { processCodeInt = (int) value; }
    }
    public bool IsExpired { get; set; }
}

public enum ProcessCode
{
    Balance
}

'There is an error in XML document (30, 10)' 从 XML 元素类型返回差异类型时出错

'There is an error in XML document (30, 10)' error while returning difference type from XML element type

c#

xml

mapping

xml-deserialization