python re.findall 匹配不同数量的模式

Question

<tr>
11:15
12:15
13:15
</tr>

<tr>
18:15
19:15
20:15
</tr>

in this case output should be: [ (11:15, 12:15, 13:15), (18:15, 19:15, 20:15) ]

我的模式：(\d\d:\d\d)[\s\S]*?(\d\d:\d\d)[\s\S]*?(\d\d:\d\d)[\s\S]*?</tr> 仅当每个 tr 标签中有 3 小时时才有效

但是如果每个 tr 标签中有 1-3 小时（格式相同 \d\d:\d\d），这应该有效。另一个例子。为此，我的模式不再有效。

<tr>12:00 13:00</tr>
<tr>14:00 15:00 16:00</tr>
<tr>12:00</tr>

Output should be: [ (12:00, 13:00, ), (14:00, 15:00, 16:00), (12:00, , ) ]

还有一件事：每个小时不只是由空格分隔，真实文件如下所示：为此，我使用了 [\s\S]*? or [\w\s<>="-/:;?|]*?。一个小时要么是简单的跨度，要么是更长的形式 .

示例：

<tr>
<span class="na">16:00</span>
<span>|</span><a href="http:/21.28.147.68/msi/default.aspx?event_id=52514&amp;typetran=1&amp;ReturnLink=http://www.kino.pl/kina/przedwiosnie/repertuar.php" class="toolBox" data-hasqtip="true" aria-describedby="qtip-0">20:45</td>
</tr>

Answer 1

我将使用 HTML 解析器 解析 HTML，找到 table 中的所有 tr 元素并拆分内容或每一行使用 str.split() - it would handle both spaces and newlines. Example using BeautifulSoup parser:

from bs4 import BeautifulSoup

data = """
<table>
    <tr>
    11:15
    12:15
    13:15
    </tr>

    <tr>
    18:15
    19:15
    20:15
    </tr>

    <tr>12:00 13:00</tr>
    <tr>14:00 15:00 16:00</tr>
    <tr>12:00</tr>
</table>"""

soup = BeautifulSoup(data, "html.parser")

result = [row.text.split() for row in soup.table.find_all("tr")]
print(result)

打印：

[['11:15', '12:15', '13:15'], 
 ['18:15', '19:15', '20:15'], 
 ['12:00', '13:00'], 
 ['14:00', '15:00', '16:00'], 
 ['12:00']]

An hour is either in simple span or in longer form .

这更好，让我们找到 tr 中匹配特定模式的每个内部元素并获取文本

[[elm.strip() for elm in row.find_all(text=re.compile(r"\d\d:\d\d"))] 
 for row in soup.table.find_all("tr")]

Answer 2

如果你更喜欢正则表达式，你可以使用这个：

found = []
for group in re.findall(r'(\d\d:\d\d.*){1,3}</tr>', data, re.DOTALL):
    found.append(re.findall(r'(\d\d:\d\d)', group, re.DOTALL))
# found == [['12:00', '13:00'], ['14:00', '15:00', '16:00'], ['12:00']]

Answer 3

使用正则表达式试试这个解决方案：

import re

input = """
<tr>
11:15
12:15
13:15
</tr>

<tr>
18:15
19:15
20:15
</tr>

<tr>12:00 13:00</tr>
<tr>14:00 15:00 16:00</tr>
<tr>12:00</tr>
"""

print [ re.findall('(\d\d:\d\d)', tr) for tr in re.findall('<tr>([^<]*)</tr>', input)]

输出：

[['11:15', '12:15', '13:15'], 
 ['18:15', '19:15', '20:15'], 
 ['12:00', '13:00'], 
 ['14:00', '15:00', '16:00'], 
 ['12:00']]

python re.findall 匹配不同数量的模式

python re.findall pattern for different number of matches

python

regex

findall