Spring-引导-错误处理

Question

我正在尝试在 Spring-Boot 中为我的控制器编写错误处理程序，以捕获大多数可能的错误（Spring、sql 等）。到目前为止，我能够得到 JSON 的 Null 响应，但是我无法将任何数据放入其中。当我尝试获取错误消息时，我只收到一个空白页。

import java.io.IOException;
import java.sql.SQLException;

import javax.servlet.http.HttpServletRequest;

import org.springframework.boot.autoconfigure.web.ErrorController;
import org.springframework.web.bind.annotation.ExceptionHandler;
import org.springframework.web.bind.annotation.RequestMapping;
import org.springframework.web.bind.annotation.RestController;
import org.springframework.web.servlet.mvc.multiaction.NoSuchRequestHandlingMethodException;

@RestController
public class BasicErrorController implements ErrorController {
    private static final String ERROR_PATH = "/error";

    @RequestMapping(value=ERROR_PATH)
    @ExceptionHandler(value = {NoSuchRequestHandlingMethodException.class, SQLException.class, IOException.class, RuntimeException.class, Exception.class})
    public ErrorBody defaultErrorHandler(HttpServletRequest request, Exception e) {     
        ErrorBody eBody = new ErrorBody();         
        eBody.setMessage(e.getCause().getMessage());
        return eBody;
    }
}

import lombok.Getter;
import lombok.Setter;

@Getter
@Setter
public class ErrorBody {
    private String dateTime;
    private String exception;
    private String url;
    private String message;
}

Answer 1

通过使用 "HttpServletRequest request" 并从请求中读取信息，我能够获取有关错误的数据并将它们作为 json 正确发送。

@RequestMapping(value = ERROR_PATH)
    public ErrorBody defaultErrorHandler(HttpServletRequest request) {....}

Answer 2

这是@ExceptionHandler(Exception.class)

的一个例子

https://spring.io/blog/2013/11/01/exception-handling-in-spring-mvc

你可以使用@ControllerAdvice

package demo.controller;

import org.springframework.web.bind.WebDataBinder;
import org.springframework.web.bind.annotation.ControllerAdvice;
import org.springframework.web.bind.annotation.ExceptionHandler;
import org.springframework.web.bind.annotation.InitBinder;
import org.springframework.web.bind.annotation.ModelAttribute;

@ControllerAdvice
public class ExceptionControllerAdvice {

 @InitBinder
 public void initBinder(WebDataBinder binder) {
    System.out.println("controller advice: init binder");
}


@ExceptionHandler(Exception.class)
public String exception(Exception e) {
    System.out.println("controller advice: exception Handler");
    System.out.println(e.getMessage());
    return "error";
}

@ModelAttribute
public void modelAttribute(){
    System.out.println("controller advice:model Attribute");
}
}

Answer 3

你可以这样做：

 @ControllerAdvice
   public class ControllerExceptionTranslator {


    @ExceptionHandler(EntityNotFoundException.class)
    @ResponseStatus(HttpStatus.NOT_FOUND)
    @ResponseBody
    SimpleErrorMessage handleException(EntityNotFoundException exception){
        log.debug("Entity Not Found Exception {}",exception.getMessage());
        log.trace(exception.getMessage(),exception);
        return new SimpleErrorMessage("Entity not found","This resource was not found");
    }


    @ExceptionHandler({UsernameNotFoundException.class})
    @ResponseStatus(HttpStatus.UNAUTHORIZED)
    @ResponseBody
    SimpleErrorMessage handleException(UsernameNotFoundException exception){
        log.debug("Username not found {}",exception.getLocalizedMessage());
        log.trace(exception.getMessage(),exception);
        return new SimpleErrorMessage("Unaouthorized"," ");
    }


}

Spring-引导-错误处理

Spring-Boot - Error Handling

error-handling

spring

spring-mvc

spring-boot