如何从 url in javascript 中删除查询字符串数组

Question

我在从 URL.

中删除查询字符串数组时遇到问题

这是我的 URL -

在Chrome中，它以给定的格式显示 -

Var url = "http://mywebsite.com/innovation?agenda%5B%5D=4995&agenda%5B%5D=4993#ideaResult";

然而，在 mozilla 中它以这种格式显示 -

 http://mywebsite.com/innovation?agenda[]=4995&agenda[]=4993#ideaResult

我想删除特定的查询参数。

假设我想删除“4995”，那么最终 URL 应该是这样的-

http://mywebsite.com/innovation?agenda[]=4993#ideaResult

请帮忙

Answer 1

replace()函数呢？

var url = " http://mywebsite.com/innovation?agenda[]=4995&agenda[]=4993#ideaResult";

url = url.replace('agenda%5B%5D=4995&', '') 
url = url.replace('agenda[]=4995&', '')

Answer 2

您可以解码 url 以使其一致

即。

var url = decodeURI("http://mywebsite.com/innovation?agenda%5B%5D=4995&agenda%5B%5D=4993#ideaResult");

...然后拆分字符串并删除查询字符串。这里有一个关于这个问题的例子 Remove querystring from URL

Answer 3

decodeURI()函数根据Mozilla document:

Replaces each escape sequence in the encoded URI with the character that it represents

所以你可以像下面这样使用它：

decodeURI(window.location).replace(/agenda\[\]=4995&?/,'')

Answer 4

function removeArrayParam(key, value, sourceURL) {
   var rtn = sourceURL.split("?")[0],
       param,
       params_arr = [],
       queryString = (sourceURL.indexOf("?") !== -1) ? sourceURL.split("?")[1] : "";
   if (queryString !== "") {
       params_arr = queryString.split("&");
       for (var i = params_arr.length - 1; i >= 0; i -= 1) {
           param = params_arr[i].split("[]=")[0];
           paramValue = params_arr[i].split("[]=")[1];
           if (param === key && paramValue === value) {
               params_arr.splice(i, 1);
           }
       }
       if(params_arr.length) {
        rtn = rtn + "?" + params_arr.join("&");
       } 
   }
   return rtn;
}

这个函数会给你想要的结果。只需传递键、值和无哈希值 url.

var url = window.location.href;
var hash = window.location.hash;
var index_of_hash = url.indexOf(hash) || url.length;
var hashless_url = url.substr(0, index_of_hash);  
var desired_url = removeArrayParam(key, value, unescape(hashless_url));

Answer 5

一直在寻找 non-plugin 从查询字符串中删除数组和 non-arrays 的解决方案，然后是 re-adding。它可能会更优雅一些，但这对我的所有测试用例都非常有效。

function removeURLParameter(param, url) {
    url = decodeURI(url).split("?");
    path = url.length == 1 ? "" : url[1];
    path = path.replace(new RegExp("&?"+param+"\[\d*\]=[\w]+", "g"), "");
    path = path.replace(new RegExp("&?"+param+"=[\w]+", "g"), "");
    path = path.replace(/^&/, "");
    return url[0] + (path.length
        ? "?" + path
        : "");
}

function addURLParameter(param, val, url) {
    if(typeof val === "object") {
        // recursively add in array structure
        if(val.length) {
            return addURLParameter(
                param + "[]",
                val.splice(-1, 1)[0],
                addURLParameter(param, val, url)
            )
        } else {
            return url;
        }
    } else {
        url = decodeURI(url).split("?");
        path = url.length == 1 ? "" : url[1];
        path += path.length
            ? "&"
            : "";
        path += decodeURI(param + "=" + val);
        return url[0] + "?" + path;
    }
}

使用方法：

url = location.href;
    -> http://example.com/?tags[]=single&tags[]=promo&sold=1

url = removeURLParameter("sold", url)
    -> http://example.com/?tags[]=single&tags[]=promo

url = removeURLParameter("tags", url)
    -> http://example.com/

url = addURLParameter("tags", ["single", "promo"], url)
    -> http://example.com/?tags[]=single&tags[]=promo

url = addURLParameter("sold", 1, url)
    -> http://example.com/?tags[]=single&tags[]=promo&sold=1

当然，要更新参数，只需删除然后添加。随意为它制作一个虚拟函数。

如何从 url in javascript 中删除查询字符串数组

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