尝试将两个查询加在一起

Question

我想再添加一列来计算剩余的行数，
我不想包含我的计划数量与完成数量相匹配的行
(plan_qty != cmp_qty)

SELECT   od_f.ob_oid Order,
         Sum(plan_qty) Plan_Units,
         sum(cmp_qty) Completed_Units,
         Round(((Sum(cmp_qty)/sum(plan_qty)) * 100.00),2)Percent_Cmp,
         total_value Value,
         SUM(round(cmp_qty * unit_price,2)) cmp_value
FROM     od_f,
         om_f
WHERE    od_f.ob_oid = om_f.ob_oid
GROUP BY od_f.ob_oid, total_value
ORDER BY Percent_Cmp desc

这是一个查询，returns 我想要的新列

 SELECT   count(od_rid)
 FROM     od_f
 WHERE    od_f.plan_qty != od_f.cmp_qty
 GROUP BY od_f.ob_oid

我无法添加上面的 where 语句，因为它会影响我的结果。
我真的不知道该怎么做，将这些查询组合成一个子查询？某种工会？我不知道该怎么做。
感谢您的帮助

Answer 1

您可以根据需要使用条件聚合。虽然 COUNT() 和 CASE 可能就足够了，但我最好的猜测是 COUNT(DISTINCT):

SELECT   od_f.ob_oid Order,
         Sum(plan_qty) Plan_Units,
         sum(cmp_qty) Completed_Units,
         Round(((Sum(cmp_qty)/sum(plan_qty)) * 100.00),2)Percent_Cmp,
         total_value Value,
         SUM(round(cmp_qty * unit_price,2)) cmp_value,
         COUNT(DISTINCT CASE WHEN od_f.plan_qty <> od_f.cmp_qty THEN od_f. od_rid END) as newcol
FROM od_f JOIN
     om_f
     ON od_f.ob_oid = om_f.ob_oid
GROUP BY od_f.ob_oid, total_value
ORDER BY Percent_Cmp desc;

您还应该学习使用正确、明确的 JOIN 语法。简单规则：从不在 FROM 子句中使用逗号。

Answer 2

@GordonLinoff 解决方案对你有好处，但前提是你想计算唯一性 od_rid ，这个解决方案适用于这两种情况，使用相关查询：

SELECT   t.ob_oid Order,
         Sum(plan_qty) Plan_Units,
         sum(cmp_qty) Completed_Units,
         Round(((Sum(cmp_qty)/sum(plan_qty)) * 100.00),2)Percent_Cmp,
         total_value Value,
         SUM(round(cmp_qty * unit_price,2)) cmp_value,
         (SELECT  count(f2.od_rid) FROM od_f f2
          WHERE f2.plan_qty != f2.cmp_qty and f2.ob_oid = f.ob_oid) as newcolumn
FROM     od_f t
         INNER JOIN om_f
ON       t.ob_oid = om_f.ob_oid
GROUP BY t.ob_oid, total_value
ORDER BY Percent_Cmp desc

Answer 3

据我了解，您只需要 plan_qty 不等于 cmp_qty 的行数，试试这个：

SELECT   t.ob_oid                                       AS order,
         SUM(plan_qty)                                  AS plan_units,
         SUM(cmp_qty)                                   AS completed_units,
         ROUND(((SUM(cmp_qty)/SUM(plan_qty)) * 100),2)  AS percent_cmp,
         total_value                                    AS value,
         SUM(ROUND(cmp_qty * unit_price,2))             AS cmp_value,
         SUM(DECODE(plan_qty, cmp_qty, 0, 1))           AS rows_left
FROM     od_f t
         INNER JOIN om_f
            ON t.ob_oid = om_f.ob_oid
GROUP BY t.ob_oid, total_value
ORDER BY percent_cmp DESC;

尝试将两个查询加在一起

Trying to add two queries together

sql

informix