Swift2 - 根据另一个 INT 数组的排序顺序对多个数组进行排序

Swift2 - Sort multiple arrays based on the sorted order of another INT array

let points:[Int] = [200, 1000, 100, 500]
let people:[String] = ["Harry", "Jerry", "Hannah", "John"]
let peopleIds:[Int] = [1, 2, 3, 4]
let sex:[String] = ["Male", "Male", "Female", "Male"]

如何按点对数组进行排序?:

let points:[Int] = [1000, 500, 200, 100]
let people:[String] = ["Jerry", "John", "Harry", "Hannah"]
let peopleIds:[Int] = [2, 4, 1, 3]
let sex:[String] = ["Male", "Male", "Male", "Female"]

它不是 的副本 我试过这些答案,但没有用

创建一个按您希望的方式排序的新索引数组"descending",然后映射其他数组。

var points:[Int] = [200, 1000, 100, 500]
var people:[String] = ["Harry", "Jerry", "Hannah", "John"]
var peopleIds:[Int] = [1, 2, 3, 4]
var sex:[String] = ["Male", "Male", "Female", "Male"]


//descending order array of indexes
let sortedOrder = points.enumerate().sort({[=10=].1>.1}).map({[=10=].0})

//Map the arrays based on the new sortedOrder
points = sortedOrder.map({points[[=10=]]})
people = sortedOrder.map({people[[=10=]]})
peopleIds = sortedOrder.map({peopleIds[[=10=]]})
sex = sortedOrder.map({sex[[=10=]]})

我刚刚测试了这个解决方案,它运行良好。

这是使用您自己的数据的解决方案。

let points:[Int] = [200, 1000, 100, 500]
let people:[String] = ["Harry", "Jerry", "Hannah", "John"]
let peopleIds:[Int] = [1, 2, 3, 4]
let sex:[String] = ["Male", "Male", "Female", "Male"]

let sortedPointsEnumerateIndexes = points.enumerate().sort { [=10=].element > .element}.map { [=10=].index }


var sortedPoints:[Int] = []
var sortedPeople:[String] = []
var sortedPeopleIds:[Int] = []
var sortedSex:[String] = []

for i in sortedPointsEnumerateIndexes {
    sortedPoints.append(points[i])
    sortedPeople.append(people[i])
    sortedPeopleIds.append(peopleIds[i])
    sortedSex.append(sex[i])
}

print(sortedPoints)     // [1000, 500, 200, 100]
print(sortedPeople)     // ["Jerry", "John", "Harry", "Hannah"]
print(sortedPeopleIds)  // [2, 4, 1, 3]
print(sortedSex)        // ["Male", "Male", "Male", "Female"]

// with map
let sorted2Point = sortedPointsEnumerateIndexes.map{ points[[=10=]] }
let sorted2People = sortedPointsEnumerateIndexes.map{ people[[=10=]] }
// ....

print(sorted2Point)     // [1000, 500, 200, 100]
print(sorted2People)    // ["Jerry", "John", "Harry", "Hannah"]