How can I slice x and y coordinates from a Shapely polygon? [TypeError: 'Polygon' object is not iterable]

Question

如何从形状多边形中切出 x 和 y 坐标？

我得到以下输出：

[evaluate xyz_25_2.py]

POLYGON ((3.449182842266765 -5.876385583121159, 2.171707715501299 -3.576930354943315, 0.6387375633827332 -1.447805143667534, -3.875007884521928 6.046715600023223, -6.004133095797705 7.750015769043845, -9.581063450741024 ..........................))

Traceback (most recent call last):
 File "C:\Users\abhi\Desktop\xyz_25_2.py", line 103, in <module>
    list(concave_hull)
TypeError: 'Polygon' object is not iterable

Answer 1

您需要检索外部或内部线性环并将它们输入 numpy。然后，您可以轻松地分割坐标。

例如：

from shapely import geometry
import numpy as np

# lets create an example polygon
p = geometry.Point(0,0)
poly = p.buffer(100)

# you need to get the coordinates of the exterior (shell)
# pass these into a numpy array
shell_coords = np.array(poly.exterior)
print(shell_coords)

# you can do the same for interior (holes) as well

# then slice and dice to your heart's content
print(shell_coords[:,:1])
print(shell_coords[:,1:2])

How can I slice x and y coordinates from a Shapely polygon? [TypeError: 'Polygon' object is not iterable]

How can I slice x and y coordinates from a Shapely polygon? [TypeError: 'Polygon' object is not iterable]

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