When using map::erase() "error: passing 'const ***' as 'this' argument of '***' discards qualifiers [-fpermissive]" reported

When using map::erase() "error: passing 'const ***' as 'this' argument of '***' discards qualifiers [-fpermissive]" reported

我正在执行以下方法以从具有 map::erase() 的关联 table (map) 中删除元素:

//Method in gestion.cpp
void Gestion::EliminateObject(string nomobjetg) const{

    auto it = objectname.find(nameobjectg);

    if (it == objectname.end())
        cout << "Object not found!" << endl;
    else
        objectname.erase(it); //The error is reported in this line
}

在 header 中,我定义了以下内容:

//gestion.h
#include "objects.h"
#include <list>
#include <iostream>
#include <string>
#include <memory>
#include <map>
using namespace std;

typedef std::shared_ptr<Objects> ObjPtr;

typedef map<string, ObjPtr> Objectmap;

class Gestion
{
private:
     Objectmap objectname;

public:
    Gestion(Objectmap objectname, Groupmap groupname);
    virtual ~Gestion() {}
    virtual void EliminateObject(string nameobjectg) const;
};

其中ObjPtrObjects类型的objects虚指针。

编译时出现此错误:

error: passing ‘const Objectmap {aka const std::map<std::basic_string<char>, std::shared_ptr<Objects> >}’ as ‘this’ argument of ‘std::map<_Key, _Tp, _Compare, _Alloc>::iterator std::map<_Key, _Tp, _Compare, _Alloc>::erase(std::map<_Key, _Tp, _Compare, _Alloc>::const_iterator) [with _Key = std::basic_string<char>; _Tp = std::shared_ptr<Objects>; _Compare = std::less<std::basic_string<char> >; _Alloc = std::allocator<std::pair<const std::basic_string<char>, std::shared_ptr<Objects> > >; std::map<_Key, _Tp, _Compare, _Alloc>::iterator = std::_Rb_tree_iterator<std::pair<const std::basic_string<char>, std::shared_ptr<Objects> > >; std::map<_Key, _Tp, _Compare, _Alloc>::const_iterator = std::_Rb_tree_const_iterator<std::pair<const std::basic_string<char>, std::shared_ptr<Objects> > >]’ discards qualifiers [-fpermissive]
         objectname.erase(it);

为什么这一行报这个错?我已经看到其他一些帖子出现此类错误,但在这些情况下,问题的根本原因与方法的声明方式有关 (const)。本例问题涉及的方法是erase,我无法修改

void Gestion::EliminateObject(string nomobjetg) const

您正在尝试通过调用 objectname.erase(it) 来修改 objectname,而 const 函数不允许您这样做,除非 objectname 是 [=26] =]可变.

删除常量:

void Gestion::EliminateObject(string nomobjetg)

使 objectname 可变

mutable Objectmap objectname;