实现列表迭代器和运算符:-- ++ *
Implementing a list iterator and operators: -- ++ *
从这个问题开始:
我想实现一个列表迭代器,它可以与其他常见容器类型及其各自的迭代器互换,所以我想使用运算符,例如:--、++、* 并能够正常声明迭代器,所以:list::iterator iter = list.begin();
--、++ 运算符现在可以正常工作,但我 运行 遇到了取消引用迭代器的问题,因为结构不能 return 值:T iterator::operator*()
template <class T>
struct element {
element<T> *prev = NULL;
element<T> *next = NULL;
T data;
};
template <typename T>
class list {
public:
list::list();
element<T>* current;
struct iterator{
element<T>* iterator::operator++(){
this = *this->next; ..whatever it works
}
element<T>* iterator::operator--()
T iterator::operator*()
}
};
迭代器可能看起来像这样:
(在列表模板内声明)
struct iterator;
struct const_iterator : public std::iterator<std::bidirectional_iterator_tag, const T>
{
const_iterator() = default;
T operator*() { return itm->data; }
const T* operator->() { return &(itm->data); }
const_iterator operator++() { itm = itm->next; return *this; }
const_iterator operator--() { itm = itm->prev; return *this; }
const_iterator operator++(int) { const_iterator ret=*this; itm = itm->next; return ret; }
const_iterator operator--(int) { const_iterator ret=*this; itm = itm->prev; return ret; }
bool operator==(const_iterator oth) const { return itm==oth.itm; }
bool operator!=(const_iterator oth) const { return itm!=oth.itm; }
private:
element<T>* itm = nullptr;
const_iterator(element<T>* i) : itm(i) {}
friend
class list;
friend
struct iterator;
};
struct iterator : public std::iterator<std::bidirectional_iterator_tag, T>
{
iterator() = default;
T& operator*() { return itm->data; }
T* operator->() { return &(itm->data); }
iterator operator++() { itm = itm->next; return *this; }
iterator operator--() { itm = itm->prev; return *this; }
iterator operator++(int) { iterator ret=*this; itm = itm->next; return ret; }
iterator operator--(int) { iterator ret=*this; itm = itm->prev; return ret; }
bool operator==(iterator oth) const { return itm==oth.itm; }
bool operator!=(iterator oth) const { return itm!=oth.itm; }
operator const_iterator() { return {itm}; }
private:
element<T>* itm = nullptr;
iterator(element<T>* i) : itm(i) {}
friend
class list;
};
typedef std::reverse_iterator<iterator> reverse_iterator;
typedef std::reverse_iterator<const_iterator> const_reverse_iterator;
这需要
#include <iterator>
编译
从这个问题开始:
我想实现一个列表迭代器,它可以与其他常见容器类型及其各自的迭代器互换,所以我想使用运算符,例如:--、++、* 并能够正常声明迭代器,所以:list::iterator iter = list.begin();
--、++ 运算符现在可以正常工作,但我 运行 遇到了取消引用迭代器的问题,因为结构不能 return 值:T iterator::operator*()
template <class T>
struct element {
element<T> *prev = NULL;
element<T> *next = NULL;
T data;
};
template <typename T>
class list {
public:
list::list();
element<T>* current;
struct iterator{
element<T>* iterator::operator++(){
this = *this->next; ..whatever it works
}
element<T>* iterator::operator--()
T iterator::operator*()
}
};
迭代器可能看起来像这样:
(在列表模板内声明)
struct iterator;
struct const_iterator : public std::iterator<std::bidirectional_iterator_tag, const T>
{
const_iterator() = default;
T operator*() { return itm->data; }
const T* operator->() { return &(itm->data); }
const_iterator operator++() { itm = itm->next; return *this; }
const_iterator operator--() { itm = itm->prev; return *this; }
const_iterator operator++(int) { const_iterator ret=*this; itm = itm->next; return ret; }
const_iterator operator--(int) { const_iterator ret=*this; itm = itm->prev; return ret; }
bool operator==(const_iterator oth) const { return itm==oth.itm; }
bool operator!=(const_iterator oth) const { return itm!=oth.itm; }
private:
element<T>* itm = nullptr;
const_iterator(element<T>* i) : itm(i) {}
friend
class list;
friend
struct iterator;
};
struct iterator : public std::iterator<std::bidirectional_iterator_tag, T>
{
iterator() = default;
T& operator*() { return itm->data; }
T* operator->() { return &(itm->data); }
iterator operator++() { itm = itm->next; return *this; }
iterator operator--() { itm = itm->prev; return *this; }
iterator operator++(int) { iterator ret=*this; itm = itm->next; return ret; }
iterator operator--(int) { iterator ret=*this; itm = itm->prev; return ret; }
bool operator==(iterator oth) const { return itm==oth.itm; }
bool operator!=(iterator oth) const { return itm!=oth.itm; }
operator const_iterator() { return {itm}; }
private:
element<T>* itm = nullptr;
iterator(element<T>* i) : itm(i) {}
friend
class list;
};
typedef std::reverse_iterator<iterator> reverse_iterator;
typedef std::reverse_iterator<const_iterator> const_reverse_iterator;
这需要
#include <iterator>
编译