输出值以逗号分隔并排除最后一个逗号
Output values to be separated by commas and to exclude the last comma
我需要我的输出用逗号分隔,但我需要排除最后一个逗号,以及我将如何重新运行我的程序。我需要尽可能以最简单的方式做到这一点。这是我目前所拥有的:
System.out.print("Enter numbers (-1 to end):");
int num = input.nextInt();
int sum = 0;
String u= " ";
while (num != -1) {
sum += num;
u += num + ",";
num = input.nextInt();
}
System.out.println("Entered Numbers: " + u);
System.out.println("The Sum: " + sum);
替换
u += num + ",";
和
u += (u.length() == 1 ? "" : ",") + num;
这只会在 u
.
后附加逗号
请注意,最好使用 StringBuilder
在循环中连接字符串。
循环并将结果放入 StringBuilder
StringBuilder buf = new StringBuilder (" ");
while (num != -1) {
sum += num;
// u += num + ",";
buf.append (num).append (",");
num = input.nextInt();
}
然后打印除最后一个以外的所有内容
System.out.println (buf.substring(0, buf.length () - 1));
if (u.endsWith(",")) {
u= u.substring(0, u.length() - 1);
}
或
StringUtils.stripEnd(u, ",");
我需要我的输出用逗号分隔,但我需要排除最后一个逗号,以及我将如何重新运行我的程序。我需要尽可能以最简单的方式做到这一点。这是我目前所拥有的:
System.out.print("Enter numbers (-1 to end):");
int num = input.nextInt();
int sum = 0;
String u= " ";
while (num != -1) {
sum += num;
u += num + ",";
num = input.nextInt();
}
System.out.println("Entered Numbers: " + u);
System.out.println("The Sum: " + sum);
替换
u += num + ",";
和
u += (u.length() == 1 ? "" : ",") + num;
这只会在 u
.
请注意,最好使用 StringBuilder
在循环中连接字符串。
循环并将结果放入 StringBuilder
StringBuilder buf = new StringBuilder (" ");
while (num != -1) {
sum += num;
// u += num + ",";
buf.append (num).append (",");
num = input.nextInt();
}
然后打印除最后一个以外的所有内容
System.out.println (buf.substring(0, buf.length () - 1));
if (u.endsWith(",")) {
u= u.substring(0, u.length() - 1);
}
或
StringUtils.stripEnd(u, ",");