在 C 中创建三个具有相同 parent 的 children
Creating three children in C that have the same parent
我的问题是 children 没有相同的 parent 并且显示不正确,这是我的代码:
#include <sys/wait.h>
#include <sys/types.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main()
{
pid_t pid[3];
pid[0] = fork();
if(pid[0] == 0)
{
/* First child */
pid[1] = fork();
if(pid[1] == 0)
{
/* First child continued */
printf("Hello, I'm the first child! My PID is : %d, My PPID is: %d", getpid(), getppid());
sleep(1);
}
else
{
/* Second child */
pid[2] = fork();
if(pid[2] == 0)
{
/* Second child continued */
printf("Hello, I'm the second child! My PID is : %d, My PPID is: %d", getpid(), getppid());
sleep(1);
}
else
{
/* Third child */
printf("Hello, I'm the first child! My PID is : %d, My PPID is: %d", getpid(), getppid());
sleep(1);
}
}
}
else
{
/* Parent */
sleep(1);
wait(0);
printf("Hello, I'm the parent! My PID is : %d, My PPID is: %d", getpid(), getppid());
}
return 0;
}
截至目前,当我 运行 程序时,我将在 bash 中将其作为输出,其中 bash 的 PID 为 11446:
>Hello, I'm the third child! My PID is: 28738, My PPID is: 28735
>Hello, I'm the first child! My PID is: 28742, My PPID is: 28738
>Hello, I'm the second child! My PID is: 28743, My PPID is: 28738
>Hello, I'm the parent! My PID is: 28753, My PPID is: 11446
如何让第一个 child 首先出现,第二个 child 第二个出现,第三个 child 最后出现,并获得所有 child ren 拥有 PPID 28753
来自 man fork:
RETURN VALUE
On success, the PID of the child process is returned in the parent, and 0 is returned in the child. On failure, -1 is returned in
the parent, no child process is created, and errno is set
appropriately.
你的if
-else
条件被调换了。
我的问题是 children 没有相同的 parent 并且显示不正确,这是我的代码:
#include <sys/wait.h>
#include <sys/types.h>
#include <stdio.h>
#include <stdlib.h>
#include <unistd.h>
int main()
{
pid_t pid[3];
pid[0] = fork();
if(pid[0] == 0)
{
/* First child */
pid[1] = fork();
if(pid[1] == 0)
{
/* First child continued */
printf("Hello, I'm the first child! My PID is : %d, My PPID is: %d", getpid(), getppid());
sleep(1);
}
else
{
/* Second child */
pid[2] = fork();
if(pid[2] == 0)
{
/* Second child continued */
printf("Hello, I'm the second child! My PID is : %d, My PPID is: %d", getpid(), getppid());
sleep(1);
}
else
{
/* Third child */
printf("Hello, I'm the first child! My PID is : %d, My PPID is: %d", getpid(), getppid());
sleep(1);
}
}
}
else
{
/* Parent */
sleep(1);
wait(0);
printf("Hello, I'm the parent! My PID is : %d, My PPID is: %d", getpid(), getppid());
}
return 0;
}
截至目前,当我 运行 程序时,我将在 bash 中将其作为输出,其中 bash 的 PID 为 11446:
>Hello, I'm the third child! My PID is: 28738, My PPID is: 28735
>Hello, I'm the first child! My PID is: 28742, My PPID is: 28738
>Hello, I'm the second child! My PID is: 28743, My PPID is: 28738
>Hello, I'm the parent! My PID is: 28753, My PPID is: 11446
如何让第一个 child 首先出现,第二个 child 第二个出现,第三个 child 最后出现,并获得所有 child ren 拥有 PPID 28753
来自 man fork:
RETURN VALUE
On success, the PID of the child process is returned in the parent, and 0 is returned in the child. On failure, -1 is returned in the parent, no child process is created, and errno is set appropriately.
你的if
-else
条件被调换了。