python 子进程：检查执行的脚本是否要求用户输入

Question

import subprocess

child = subprocess.Popen(['python', 'simple.py'], stdin=subprocess.PIPE)
child.communicate('Alice')

我知道您可以通过 communicate 与执行的脚本进行通信您如何检查脚本 'simple.py' 是否要求用户输入？

simple.py 可能需要 5-10 个用户输入，因此简单地硬编码 communicate 是不够的。

[编辑]：想要解析标准输出，因为脚本是运行并返回给脚本

while True:
    if child.get_stdout() == '?':
       # send user input

Answer 1

一个简单的例子：

simple.py:

i = raw_input("what is your name\n")
print(i)
j = raw_input("What is your age\n")
print(j)

读写：

import subprocess

child = subprocess.Popen(['python2', 'simple.py'], stdin=subprocess.PIPE, stdout=subprocess.PIPE)

for line in iter(child.stdout.readline, ""):
    print(line)
    if "name" in line:
        child.stdin.write("foo\n")
    elif "age" in line:
        child.stdin.write("100\n")

输出：

what is your name

foo

What is your age

100

python 子进程：检查执行的脚本是否要求用户输入

python subprocess: check to see if the executed script is asking for user input

python

subprocess