insert age of account MYSQL 查询
insert age of account MYSQL query
找到 start_date
和 account_add_date
这两个日期的差异然后插入名为 account_age
的列的最佳方法是什么?
我需要的是用户 select start_date
说是一月。
然后他们添加的日期 account_add_date
说是三月。
相差 2 个月,所以 account_age
是 2,
然后在 4 月,2 将是 3。5 月 4 日,6 月 5 日,依此类推
有人知道怎么做吗?
我当前的插入查询MODEL
function create_bank()
{
$this->load->helper('date');
$new_bank_acc_insert_data = array(
'bank_name' => $this->input->post('bank_name'),
'interest' => ($this->input->post('interest') / 100),
'start_amount' => $this->input->post('start_amount'),
'length' => $this->input->post('length'),
'start_date' => date('Y-m-d',strtotime($this->input->post('start_date'))),
'mem_id' => $this->session->userdata('id'),
'account_add_date' => $this->current_date()
);
$insert = $this->db->insert('bank', $new_bank_acc_insert_data);
return $insert;
}
关于查找帐户年龄的想法
SELECT DATEDIFF('start_date','account_add_date')
SELECT
(
12* (YEAR(account_add_date) - YEAR(start_date)) +
(MONTH(account_add_date) - MONTH(start_date))
) AS differenceInMonth
FROM
YOUR_TABLE
尽管 DATEDIFF
函数 returns 两个日期的天数差异比月数差异更准确
解释:
示例:
start_date = 2014 March
account_add_date = 2015 January
YEAR(account_add_date) = 2015
YEAR(start_date) = 2014
MONTH(account_add_date) = 1
MONTH(start_date) = 3
So according to the query:
12 * (2015-2014) + (1-3) = 12 * 1 - 2 = 10 (Months)
找到 start_date
和 account_add_date
这两个日期的差异然后插入名为 account_age
的列的最佳方法是什么?
我需要的是用户 select start_date
说是一月。
然后他们添加的日期 account_add_date
说是三月。
相差 2 个月,所以 account_age
是 2,
然后在 4 月,2 将是 3。5 月 4 日,6 月 5 日,依此类推
有人知道怎么做吗?
我当前的插入查询MODEL
function create_bank()
{
$this->load->helper('date');
$new_bank_acc_insert_data = array(
'bank_name' => $this->input->post('bank_name'),
'interest' => ($this->input->post('interest') / 100),
'start_amount' => $this->input->post('start_amount'),
'length' => $this->input->post('length'),
'start_date' => date('Y-m-d',strtotime($this->input->post('start_date'))),
'mem_id' => $this->session->userdata('id'),
'account_add_date' => $this->current_date()
);
$insert = $this->db->insert('bank', $new_bank_acc_insert_data);
return $insert;
}
关于查找帐户年龄的想法
SELECT DATEDIFF('start_date','account_add_date')
SELECT
(
12* (YEAR(account_add_date) - YEAR(start_date)) +
(MONTH(account_add_date) - MONTH(start_date))
) AS differenceInMonth
FROM
YOUR_TABLE
尽管 DATEDIFF
函数 returns 两个日期的天数差异比月数差异更准确
解释:
示例:
start_date = 2014 March
account_add_date = 2015 January
YEAR(account_add_date) = 2015
YEAR(start_date) = 2014
MONTH(account_add_date) = 1
MONTH(start_date) = 3
So according to the query:
12 * (2015-2014) + (1-3) = 12 * 1 - 2 = 10 (Months)