如何在c中的结构中实现变量？

Question

这不是完整的程序

struct p
{
int a;
int b;
int c;
};
void main()
{
int op,i,j,to,from,a,b,c;
struct p pr[3];
clrscr();
for(i=1;i<4;i++)
{
    pr[i].a=0;
    pr[i].b=0;
    pr[i].c=0;
    printf("P%d %d %d %d\n",i,pr[i].a,pr[i].b,pr[i].c);
}
do{

printf("\nEnter the option you want to execute:\n1. Internal Event\n2. Send Message \n3. Exit \n\n");
scanf("%d",&op);


switch(op)
{
    case 1:
    printf("\nEnter the process for which the internal event takes place: ");
    scanf("%d",&j);

j 的值将从 1 到 3 不等我想在这里做的是：如果j=1， pr[1].a=pr[1].a+1; 我想自动更新 j 的值，而不是为 j 实现 switch case pr[j]a/b/c

谁能帮忙解决一下。 PS: 我正在尝试为向量时钟实现一个 C 程序

Answer 1

如果struct不变，就相当于一个int数组。然后你可以使用联合并使用最漂亮的东西：

typedef union uBoth {
    struct
    {
        int a;
        int b;
        int c;
    } p;
    int q[3];
};

void main()
{
    int op,i,j,to,from,a,b,c;
    union uBoth pr[3];

    clrscr();
    for(i=0; i<3; i++)
    {
        for (j=0; j<3; j++)
            pr[i].q[j]= 0;
        printf("P%d %d %d %d\n",i+1, pr[i].p.a, pr[i].p.b, pr[i].p.c);
    }
    do {
        printf("\nEnter the option you want to execute:\n1. Internal Event\n2. Send Message \n3. Exit \n\n");
        scanf("%d",&op);
        switch(op)
        {
            case 1:
                printf("\nEnter the process for which the internal event takes place: ");
                scanf("%d",&j);
                pr[j-1].p.a= 1;
        }
    } while(1);
}

如何在c中的结构中实现变量？

How to implement variables in a structure in c?

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structure