使用 python 从坐标元组中查找平均坐标
Find average coordinate from a coordinate tuple with python
你好，我有一个黑色的背景，有一个白点。我有白色像素的所有坐标。
points = np.where(image==255)
"print points" 给了我这个输出，我看到元组列表中有两个数组：
(array([119, 119, 119, 119, 120, 120, 120, 120, 120, 120, 120, 120, 120,
120, 120, 120, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121,
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152, 152, 152, 152, 152, 152, 152, 152, 152, 153, 153, 153, 153,
153, 153, 153, 153, 153, 153, 153, 153, 153, 154, 154, 154, 154, 154]), array([77, 78, 79, 80, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 71,
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81, 82, 83, 84, 85, 86, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82,
83, 84, 76, 77, 78, 79, 80]))
我想求平均坐标。看起来像 (x,y)。
我该怎么做？
您已经可以使用 python 的内置函数来计算每个元组部分的总和。不要忘记检查 len(points[n]) > 0 以避免被零除异常。
myAvgPoint = (sum(points[0])/len(points[0]),sum(points[1])/len(points[1]))
np.where returns 一个与 2, N 数组同构的元组，您需要在 N 白点上计算平均值，即在第二个轴上，从 0 算起，是 axis=1 --- 最终你的计算只是一个线性
np.average(np.where(image==255), axis=1)
np.average(np.where(图像==255), 轴=1)
这才是真正的解决办法。
我的结果是：
[136.6045082 78.33913934]
你好，我有一个黑色的背景，有一个白点。我有白色像素的所有坐标。
points = np.where(image==255)
"print points" 给了我这个输出，我看到元组列表中有两个数组：
(array([119, 119, 119, 119, 120, 120, 120, 120, 120, 120, 120, 120, 120,
120, 120, 120, 121, 121, 121, 121, 121, 121, 121, 121, 121, 121,
121, 121, 121, 121, 121, 121, 122, 122, 122, 122, 122, 122, 122,
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67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83,
84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 62, 63, 64, 65, 66,
67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83,
84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 95, 62, 63, 64, 65, 66,
67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83,
84, 85, 86, 87, 88, 89, 90, 91, 92, 93, 94, 63, 64, 65, 66, 67, 68,
69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85,
86, 87, 88, 89, 90, 91, 92, 93, 94, 63, 64, 65, 66, 67, 68, 69, 70,
71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87,
88, 89, 90, 91, 92, 93, 64, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74,
75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91,
92, 93, 65, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79,
80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 91, 92, 65, 66, 67, 68,
69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85,
86, 87, 88, 89, 90, 91, 66, 67, 68, 69, 70, 71, 72, 73, 74, 75, 76,
77, 78, 79, 80, 81, 82, 83, 84, 85, 86, 87, 88, 89, 90, 67, 68, 69,
70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82, 83, 84, 85, 86,
87, 88, 89, 69, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82,
83, 84, 85, 86, 87, 88, 70, 71, 72, 73, 74, 75, 76, 77, 78, 79, 80,
81, 82, 83, 84, 85, 86, 72, 73, 74, 75, 76, 77, 78, 79, 80, 81, 82,
83, 84, 76, 77, 78, 79, 80]))
我想求平均坐标。看起来像 (x,y)。
我该怎么做？
您已经可以使用 python 的内置函数来计算每个元组部分的总和。不要忘记检查 len(points[n]) > 0 以避免被零除异常。
myAvgPoint = (sum(points[0])/len(points[0]),sum(points[1])/len(points[1]))
np.where returns 一个与 2, N 数组同构的元组，您需要在 N 白点上计算平均值，即在第二个轴上，从 0 算起，是 axis=1 --- 最终你的计算只是一个线性
np.average(np.where(image==255), axis=1)
np.average(np.where(图像==255), 轴=1)
这才是真正的解决办法。
我的结果是： [136.6045082 78.33913934]