MySQL 限制和偏移错误

Question

我正在制作此分页，但我的查询出现此错误

Error Number: 1064

You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'LIMIT 0 , 10' at line 9

SELECT job_availability.JOB_CODE, job_titles.JOB_NAME, job_availability.AVAILABILITY FROM job_titles LEFT JOIN job_availability ON job_availability.JOB_CODE = job_titles.JOB_CODE ORDER BY job_titles.JOB_NAME, LIMIT 0 , 10

我正在尝试这样做

function get_department_list($limit, $start)
{
    $sql = 'select var_dept_name, var_emp_name from tbl_dept, tbl_emp where tbl_dept.int_hod = tbl_emp.int_id order by var_dept_name limit ' . $start . ', ' . $limit;
    $query = $this->db->query($sql);
    return $query->result();
}

我的密码是

public function get_list($limit , $start){

    $sql = ('SELECT 
                job_availability.JOB_CODE, 
                job_titles.JOB_NAME, 
                job_availability.AVAILABILITY
            FROM job_titles
            LEFT JOIN job_availability
            ON job_availability.JOB_CODE = job_titles.JOB_CODE
            ORDER BY job_titles.JOB_NAME,
            LIMIT ? , ?');
    $data = array($start, $limit);
    $query =  $this->db->query($sql, $data);
}

我认为我的代码没有问题，所以我不确定错误是什么。我的 MySQL 版本是 5.6.24.

Answer 1

您在 order by 子句末尾的 limit 子句之前有一个多余的逗号 (,)。只需删除它，你应该没问题：

SELECT 
    job_availability.JOB_CODE, 
    job_titles.JOB_NAME, 
    job_availability.AVAILABILITY
FROM job_titles
LEFT JOIN job_availability
ON job_availability.JOB_CODE = job_titles.JOB_CODE
ORDER BY job_titles.JOB_NAME
-- Comma removed here ------^
LIMIT ? , ?

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