使用 GPars 分派异步任务并立即 return

Use GPars to dispatch an async task and return immediately

我想要一个分派异步任务的方法,returns 立即。我不需要等待结果。 我想要这样的东西工作:

/**
* runs a job and return job id for later montoring.
*/
def int runJob(){
  int jobId = createJob() // returns immediately
  task{
    doSomthingThatTakesSomeTime()
  }.then {stepResult-> doSmtgElse(stepResult)}
  return jobId
}

在上述情况下,任务不会 运行,因为没有调用 .get() ,但是,如果我执行 .get() ,该方法将不会 return jobId 直到任务完成。

我怎样才能分派任务并且仍然return立即?

您可以 运行 此示例作为 Groovy 脚本:

    @Grapes(
        @Grab(group='org.codehaus.gpars', module='gpars', version='1.2.1')
    )

    import java.util.concurrent.*
    import groovyx.gpars.*

    def doSomethingThatTakesSomeTime(){
        println "calculating..."
        for(long i: 0..100){
            Thread.sleep(i)
        }

        println "*done*"
        "Done with doSomethingThatTakesSomeTime"
    }

    def doSomethingElse(){
        for(int x:0..1000) print "."
        println "doSomethingElse done."
    }


    /**
    * runs a job and return job id for later montoring.
    */
    def runJob(){
        GParsPool.withPool(){
            Future future = createJob() // returns immediately
            doSomethingElse() //Do someting else while the async process is running
            //Ok, thats done, but the longer runningprocess is still running, return the future
            future
        }
    }

    Future createJob(){
        //create a new closure, which starts the original closure on a thread pool
        Closure asyncFunction = { doSomethingThatTakesSomeTime() }.async()

        //Invoke the function, return a Future
        asyncFunction()
    }

    def job = runJob()
    //println "\n\nResult is: " + job.get()

如果您 运行 脚本 "as-is",您将看到它 运行s 并且长 运行ning 作业会打印 *done* 指示它实际上 运行 完成了,即使底部调用 Future.get() 的行被注释掉并且从未调用过。

如果您取消注释最后一行,您将看到调用 Future.get()

后打印的结果

阅读@pczeus 的回答和 Jérémie B 的评论后,我想到了这个:

import static groovyx.gpars.dataflow.Dataflow.task

def int longTask(){
    def counter = 0
    10.times {
        println "longTask_${counter}"
        counter++
        sleep 10
    }
    counter
}

def int getSomeString() {
    def jobId=55
    task {
        longTask()

    }.then { num -> println "completed running ${num} times" }
    return  jobId
}
println getSomeString()

sleep 2000

这会打印:

longTask_0
55
longTask_1
longTask_2
longTask_3
longTask_4
longTask_5
longTask_6
longTask_7
longTask_8
longTask_9
completed running 10 times

这就是我的意图: longTask() 在后台 运行,getSomeString() 不等待长任务就重新运行,只要程序仍然是 运行(因此睡眠 2000),即使是子句'then' 部分被执行