使用循环查找均值和标准差

Question

我的目标是计算从用户输入中获得的 10 个数字的均值和标准差。

我在 class.

中只学习了 while 循环

问题： 我如何将每个用户输入（在循环内）分配给一个单独的变量，以便稍后与平均值进行比较，找出标准偏差？

（我的class中没有教过数组，所以，我必须不使用数组来解决这个问题）

我用很长很乏味的方式完成了这个程序，但如果需要的话可以提供更多代码来证明我可以做 while 循环来找到均值。

import java.util.Scanner;

public class StandardDev
{
   public static void main (String[] args)
   {
   Scanner input = new Scanner (System.in);

   double num1 = 0, num2 = 0, num3 = 0, num4 = 0, num5 = 0, num6 = 0, num7 = 0, num8 = 0, num9 = 0, num10 = 0, total = 0, mean = 0, stDev1 = 0, stDev2 = 0, sum = 0;

   System.out.println("Enter 10 numbers: ");
   num1 = input.nextDouble();
   num2 = input.nextDouble();
   num3 = input.nextDouble();
   num4 = input.nextDouble();
   num5 = input.nextDouble();
   num6 = input.nextDouble();
   num7 = input.nextDouble();
   num8 = input.nextDouble();
   num9 = input.nextDouble();
   num10 = input.nextDouble();

   sum = num1+num2+num3+num4+num5+num6+num7+num8+num9+num10;

   mean = sum / (double) 10;

   stDev1 = Math.pow(num1 - mean, 2) + Math.pow(num2 - mean, 2) + Math.pow(num3 - mean, 2) + Math.pow(num4 - mean, 2) + Math.pow(num5 - mean, 2) + 
   Math.pow(num6 - mean, 2) + Math.pow(num7 - mean, 2) + Math.pow(num8 - mean, 2) + Math.pow(num9 - mean, 2) + Math.pow(num10 - mean, 2);

   stDev2 = Math.sqrt(stDev1 / 10);

   System.out.println ("The mean is " + mean + ".");
   System.out.println ("The standard deviation is " + stDev2 + ".");
   }
}

这是我找到平均值的方法。我的逻辑告诉我，如果我可以单独访问这些输入以从均值和平方中减去，我只能找到标准偏差。不知道怎么样..

import java.util.Scanner;

public class JTillman03_45
{
   public static void main (String[] args)
   {
   Scanner input = new Scanner (System.in);

   int count = 0, total = 0;

   double mean, stDev = 0;

   System.out.println("Enter a digit: ");
   int number = input.nextInt();

   while (count < 9){
      total += number;
      count++;


   System.out.println("Enter a digit: ");
   number = input.nextInt();
   }

   mean = total / (double) count;

   System.out.println("The mean of those numbers is: " + mean); 
   System.out.println("The standard deviation of those numbers is: " + stDev); 
  }
}

Answer 1

使用while循环，迭代input.nextDouble()的值作为循环的条件。只要有输入，循环就会继续。同时，记录输入的数量和数字的总和。只需使用这 2 个数字，您就可以计算平均值和标准偏差。如果您查看 stDev1，您会发现它只是数字之和减去均值乘以 10（或输入计数）。平均值只是总和除以输入计数。如果您需要更多解释，请告诉我。我将很快添加一些示例代码。

public class StandardDev {

    public static void main(String[] args) {
        Scanner input = new Scanner(System.in);

        while (input.hasNext()) {
            sum += input.nextDouble();
            count++;
        }
        mean = sum / count;
        stdDev = sum - (count * mean);

        System.out.println("The mean is " + mean + ".");
        System.out.println("The standard deviation is " + stdDev + ".");
    }
}

Answer 2

要对 10 个用户输入的数字求和，您可以仅使用一个变量和 += 运算符来跟踪总和。不需要那么多变量，这就是循环的作用！例如，

double sum = 0;
Scanner input = new Scanner (System.in);
int counter = 1;
System.out.println("Enter 10 numbers: ");
//adds up 10 user-inputted numbers
while(counter <= 10){
     sum += input.nextDouble();
     //how the loop will end after 10th iteration
     counter++;
}
double mean = sum/10; //no need for double cast here since sum is a double

如果没有数组，就很难使用循环来计算标准差，因为我们需要访问各个数字才能找到标准差。因此，您的解决方案确实是唯一的方法，除非我们让用户使用类似于上面的 while 循环再次输入相同的 10 个数字来查找方差。例如，

//reset counter
counter = 1;
double variance = 0;
System.out.println("Enter 10 numbers: ");

while(counter <= 10){
     variance += Math.pow(input.nextDouble()-mean,2);
     counter++;
}
double stdDev = Math.sqrt(variance/10);
System.out.println ("The mean is " + mean + ".");
System.out.println ("The standard deviation is " + stdDev + ".");

Answer 3

这是带循环的更新代码。

public static void main(String[] args) {
    Scanner input = new Scanner(System.in);
    double sum = 0;
    double sqSum = 0;

    System.out.println("Enter 10 numbers: separte by space");
    for ( int i = 0 ; i < 10 ; i++){
        double val = input.nextDouble();
        sum += val;
        sqSum += val * val;
    }

    double mean = sum / 10;
    double stdDev = sqSum / 10 - mean * mean;
    System.out.println("The mean is " + mean + ".");
    System.out.println("The standard deviation is " + stdDev + ".");
}

Answer 4

你真的需要存储所有的整数吗？如果不是，您可以使用以下三个值计算平均值和标准偏差：

输入了多少个数字（在你的问题中，它是一个固定值10）。
所有数字的总和。
数字的平方和。

给出

double count = 10.0;   // is 10.0 for your problem
double sum1 = 0.0;    // sum of the numbers
double sum2 = 0.0;    // sum of the squares
int i;
for (i=0; i < 10; i++) {
  System.out.println("Enter 10 numbers: ");
  double n = input.nextDouble();
  sum1 += n;
  sum2 += n * n;
}
double average = sum1 / count;
double variance = (count * sum2 - sum1 * sum1) / (count * count);
double stdev = Math.sqrt(variance);

使用循环查找均值和标准差

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