计算每个 {country,city,year,month} 组的 运行 总数
Calculate running total for each {country,city,year,month} group
我需要根据两个 table 的连接计算每个国家、城市、年份和月份的 运行 总数。所有数据的查询是这个：
编辑：与 TD_MONTH table 的连接操作不是强制性的。
SELECT costs.CITY,
costs.COUNTRY,
months.ID,
costs.ID_YEAR,
SUM (costs.AMOUNT) AMOUNT
FROM TH_COSTS costs
JOIN
TD_MONTH months
ON (costs.ID_MES = months.YEARMONTH)
GROUP BY costs.COUNTRY,
costs.CITY,
costs.ID_YEAR,
months.ID
ORDER BY costs.COUNTRY,
costs.CITY,
costs.ID_YEAR,
months.ID;
此网格上的结果：
+---------+--------+-------+------+-----------+
| Country | City | Month | Year | Amount |
+---------+--------+-------+------+-----------+
| Spain | Madrid | 4 | 2014 | 396061,7 |
| Spain | Madrid | 5 | 2014 | 315725,25 |
| Spain | Madrid | 6 | 2014 | 16390 |
| Spain | Madrid | 7 | 2014 | 85296 |
| Spain | Madrid | 8 | 2014 | 10443,25 |
| Spain | Madrid | 12 | 2014 | 17500 |
| Spain | Madrid | 1 | 2015 | 353566 |
| Spain | Madrid | 2 | 2015 | 382729 |
| Spain | Madrid | 3 | 2015 | 261026 |
| Spain | Madrid | 4 | 2015 | 304258 |
| Spain | Madrid | 5 | 2015 | 259893 |
| Spain | Madrid | 6 | 2015 | 217296 |
| Spain | Madrid | 7 | 2015 | 461769 |
| Spain | Madrid | 8 | 2015 | 456990,5 |
| Spain | Madrid | 9 | 2015 | 219020 |
| Spain | Madrid | 10 | 2015 | 242796 |
| Spain | Madrid | 11 | 2015 | 134197 |
| Spain | Madrid | 12 | 2015 | 91901,9 |
+---------+--------+-------+------+-----------+
从上面的结果我需要下一个结果：
+---------+--------+-------+------+-----------+
| Country | City | Month | Year | Amount |
+---------+--------+-------+------+-----------+
| Spain | Madrid | 1 | 2014 | 0 |
| Spain | Madrid | 2 | 2014 | 0 |
| Spain | Madrid | 3 | 2014 | 0 |
| Spain | Madrid | 4 | 2014 | 396061,7 |
| Spain | Madrid | 5 | 2014 | 711786,95 |
| Spain | Madrid | 6 | 2014 | 728176,95 |
| Spain | Madrid | 7 | 2014 | 813472,95 |
| Spain | Madrid | 8 | 2014 | 823916,2 |
| Spain | Madrid | 9 | 2014 | 841416,2 |
| Spain | Madrid | 10 | 2014 | 1194982,2 |
| Spain | Madrid | 11 | 2014 | 1577711,2 |
| Spain | Madrid | 12 | 2014 | 1595211,2 |
| Spain | Madrid | 1 | 2015 | 353566 |
| Spain | Madrid | 2 | 2015 | 736295 |
| Spain | Madrid | 3 | 2015 | 997321 |
| Spain | Madrid | 4 | 2015 | 1301579 |
| Spain | Madrid | 5 | 2015 | 1561472 |
| Spain | Madrid | 6 | 2015 | 1778768 |
| Spain | Madrid | 7 | 2015 | 2240537 |
| Spain | Madrid | 8 | 2015 | 2697527,5 |
| Spain | Madrid | 9 | 2015 | 2916547,5 |
| Spain | Madrid | 10 | 2015 | 3159343,5 |
| Spain | Madrid | 11 | 2015 | 3293540,5 |
| Spain | Madrid | 12 | 2015 | 3385442,4 |
+---------+--------+-------+------+-----------+
编辑：起始字段 table:
+----------+----------+--------+--------+--------+--------+-----------+---------+------+
| AMOUNT_1 | AMOUNT_2 | STREET | CITY 1 | MONTH | CITY 2 | CONTINENT | COUNTRY | YEAR |
+----------+----------+--------+--------+--------+--------+-----------+---------+------+
首先想到的是使用四个嵌套循环，但这是一个非常耗时的解决方案。
有什么想法吗？
您可以尝试以下操作：
with test(Country, City, Year, Month,amount) as
(
select 'Spain', 'Madrid', 2014, 4, 1 from dual union all
select 'Spain', 'Madrid', 2014, 5, 1 from dual union all
select 'Spain', 'Madrid', 2014, 6, 1 from dual union all
select 'Spain', 'Madrid', 2014, 7, 1 from dual union all
select 'Spain', 'Madrid', 2014, 8, 1 from dual union all
select 'Spain', 'Madrid', 2014, 9, 1 from dual union all
select 'Spain', 'Madrid', 2014, 10, 1 from dual union all
select 'Spain', 'Madrid', 2014, 11, 1 from dual union all
select 'Spain', 'Madrid', 2014, 12, 1 from dual union all
select 'Spain', 'Madrid', 2015, 1, 1 from dual union all
select 'Spain', 'Madrid', 2015, 2, 1 from dual union all
select 'UK', 'London', 2014, 7, 10 from dual union all
select 'UK', 'London', 2014, 8, 10 from dual union all
select 'UK', 'London', 2014, 9, 10 from dual union all
select 'UK', 'London', 2014, 10, 10 from dual union all
select 'UK', 'London', 2014, 11, 10 from dual union all
select 'UK', 'London', 2014, 12, 10 from dual union all
select 'UK', 'London', 2015, 1, 10 from dual union all
select 'UK', 'London', 2015, 2, 10 from dual
)
select country, city, year, month,
sum(amount) over ( partition by country, city, year order by month)
from test
它计算 运行 总数，按月排序并按年、国家和城市分组
我需要根据两个 table 的连接计算每个国家、城市、年份和月份的 运行 总数。所有数据的查询是这个：
编辑：与 TD_MONTH table 的连接操作不是强制性的。
SELECT costs.CITY,
costs.COUNTRY,
months.ID,
costs.ID_YEAR,
SUM (costs.AMOUNT) AMOUNT
FROM TH_COSTS costs
JOIN
TD_MONTH months
ON (costs.ID_MES = months.YEARMONTH)
GROUP BY costs.COUNTRY,
costs.CITY,
costs.ID_YEAR,
months.ID
ORDER BY costs.COUNTRY,
costs.CITY,
costs.ID_YEAR,
months.ID;
此网格上的结果：
+---------+--------+-------+------+-----------+
| Country | City | Month | Year | Amount |
+---------+--------+-------+------+-----------+
| Spain | Madrid | 4 | 2014 | 396061,7 |
| Spain | Madrid | 5 | 2014 | 315725,25 |
| Spain | Madrid | 6 | 2014 | 16390 |
| Spain | Madrid | 7 | 2014 | 85296 |
| Spain | Madrid | 8 | 2014 | 10443,25 |
| Spain | Madrid | 12 | 2014 | 17500 |
| Spain | Madrid | 1 | 2015 | 353566 |
| Spain | Madrid | 2 | 2015 | 382729 |
| Spain | Madrid | 3 | 2015 | 261026 |
| Spain | Madrid | 4 | 2015 | 304258 |
| Spain | Madrid | 5 | 2015 | 259893 |
| Spain | Madrid | 6 | 2015 | 217296 |
| Spain | Madrid | 7 | 2015 | 461769 |
| Spain | Madrid | 8 | 2015 | 456990,5 |
| Spain | Madrid | 9 | 2015 | 219020 |
| Spain | Madrid | 10 | 2015 | 242796 |
| Spain | Madrid | 11 | 2015 | 134197 |
| Spain | Madrid | 12 | 2015 | 91901,9 |
+---------+--------+-------+------+-----------+
从上面的结果我需要下一个结果：
+---------+--------+-------+------+-----------+
| Country | City | Month | Year | Amount |
+---------+--------+-------+------+-----------+
| Spain | Madrid | 1 | 2014 | 0 |
| Spain | Madrid | 2 | 2014 | 0 |
| Spain | Madrid | 3 | 2014 | 0 |
| Spain | Madrid | 4 | 2014 | 396061,7 |
| Spain | Madrid | 5 | 2014 | 711786,95 |
| Spain | Madrid | 6 | 2014 | 728176,95 |
| Spain | Madrid | 7 | 2014 | 813472,95 |
| Spain | Madrid | 8 | 2014 | 823916,2 |
| Spain | Madrid | 9 | 2014 | 841416,2 |
| Spain | Madrid | 10 | 2014 | 1194982,2 |
| Spain | Madrid | 11 | 2014 | 1577711,2 |
| Spain | Madrid | 12 | 2014 | 1595211,2 |
| Spain | Madrid | 1 | 2015 | 353566 |
| Spain | Madrid | 2 | 2015 | 736295 |
| Spain | Madrid | 3 | 2015 | 997321 |
| Spain | Madrid | 4 | 2015 | 1301579 |
| Spain | Madrid | 5 | 2015 | 1561472 |
| Spain | Madrid | 6 | 2015 | 1778768 |
| Spain | Madrid | 7 | 2015 | 2240537 |
| Spain | Madrid | 8 | 2015 | 2697527,5 |
| Spain | Madrid | 9 | 2015 | 2916547,5 |
| Spain | Madrid | 10 | 2015 | 3159343,5 |
| Spain | Madrid | 11 | 2015 | 3293540,5 |
| Spain | Madrid | 12 | 2015 | 3385442,4 |
+---------+--------+-------+------+-----------+
编辑：起始字段 table:
+----------+----------+--------+--------+--------+--------+-----------+---------+------+
| AMOUNT_1 | AMOUNT_2 | STREET | CITY 1 | MONTH | CITY 2 | CONTINENT | COUNTRY | YEAR |
+----------+----------+--------+--------+--------+--------+-----------+---------+------+
首先想到的是使用四个嵌套循环，但这是一个非常耗时的解决方案。
有什么想法吗？
您可以尝试以下操作：
with test(Country, City, Year, Month,amount) as
(
select 'Spain', 'Madrid', 2014, 4, 1 from dual union all
select 'Spain', 'Madrid', 2014, 5, 1 from dual union all
select 'Spain', 'Madrid', 2014, 6, 1 from dual union all
select 'Spain', 'Madrid', 2014, 7, 1 from dual union all
select 'Spain', 'Madrid', 2014, 8, 1 from dual union all
select 'Spain', 'Madrid', 2014, 9, 1 from dual union all
select 'Spain', 'Madrid', 2014, 10, 1 from dual union all
select 'Spain', 'Madrid', 2014, 11, 1 from dual union all
select 'Spain', 'Madrid', 2014, 12, 1 from dual union all
select 'Spain', 'Madrid', 2015, 1, 1 from dual union all
select 'Spain', 'Madrid', 2015, 2, 1 from dual union all
select 'UK', 'London', 2014, 7, 10 from dual union all
select 'UK', 'London', 2014, 8, 10 from dual union all
select 'UK', 'London', 2014, 9, 10 from dual union all
select 'UK', 'London', 2014, 10, 10 from dual union all
select 'UK', 'London', 2014, 11, 10 from dual union all
select 'UK', 'London', 2014, 12, 10 from dual union all
select 'UK', 'London', 2015, 1, 10 from dual union all
select 'UK', 'London', 2015, 2, 10 from dual
)
select country, city, year, month,
sum(amount) over ( partition by country, city, year order by month)
from test
它计算 运行 总数，按月排序并按年、国家和城市分组