复制数据库中的所有单行 table

Question

我有这个 table 有多列。主键是 (type,ref,code)，行类型为 t1，t2，有两种状态有效 (V) 和无效 (I)。

状态 t1 中的每个无效行都应该在状态 t2 中有一个有效行，但是我的 table 已经有一些状态为无效的行，这些行在状态 t2.

中没有有效行

示例：

   type    |  ref   |  code   | state .....
----------------------------------------
   t1      |  1     | c1      | V
   t1      |  2     | c1      | V
   t1      |  3     | c1      | I
   t2      |  3     | c1      | V
   t1      |  4     | c1      | V
   t1      |  5     | c1      | I

所以我需要复制缺失的行

我正在使用

INSERT INTO table (type,ref,code,state)
SELECT 't2',ref,code,'V' FROM table
WHERE EXISTS (SELECT ref,code,count(*) from table GROUP BY ref,code HAVING count(*)=1)
AND state='I'

但我得到

 Violation of PRIMARY KEY

我试过

WHERE NOT EXISTS (SELECT ref,code,count(*) from table GROUP BY ref,code HAVING count(*)>1)
AND state='I'

并没有发生任何事情。知道如何执行此操作吗？

Answer 1

如果是主键，必须是唯一的，不能为空定义。因此，如果您需要两个或更多状态，则需要另一个 table，或另一个字段（如果只有两个），而不是寻求查询

Answer 2

您可以使用以下查询来获取要重复的行：

SELECT type, ref, code, state
FROM mytable AS t1
WHERE state = 'I' AND type = 't1' AND 
      NOT EXISTS (SELECT 1
                  FROM mytable AS t2
                  WHERE t1.ref = t2.ref AND t1.code = t2.code AND
                        state = 'V' AND type = 't2')

因此，INSERT 语句可以如下所示：

INSERT INTO mytable 
SELECT 't2', ref, code, 'V'
FROM mytable AS t1
WHERE state = 'I' AND type = 't1' AND 
      NOT EXISTS (SELECT 1
                  FROM mytable AS t2
                  WHERE t1.ref = t2.ref AND t1.code = t2.code AND
                        state = 'V' AND type = 't2')

Answer 3

试试这个代码。

  INSERT INTO #TAB
  SELECT 't2', REF, CODE, 'V' FROM #TAB WHERE stateS='I' 
  AND REF NOT IN (SELECT REF FROM #TAB WHERE stateS='V' AND typeSS='T2')

复制数据库中的所有单行 table

Duplicate All single rows in database table

sql

sql-server

not-exists

sql-insert