onClick 事件不起作用 Android

Question

我遇到了一个错误，这个错误很常见，因为我在网上看到了几个解决方案，都是一样的。我曾尝试在我的 android 代码上执行此操作，但它不起作用。

我有一个按钮。这个按钮，取决于微调器上的文本，应该让我转到一个页面或另一个页面。

这是按钮的 xml 代码：

<Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/lancer"
    android:id="@+id/startButton"
    android:layout_alignParentRight="true"
    android:layout_alignParentBottom="true"
    android:clickable="true"
    android:onClick="jumpTo"/>

及其 java class:

public class Admin extends AppCompatActivity implements View.OnClickListener {

Spinner spinner_event;
Spinner spinner_activity;
Spinner spinner_wallpaper;
ArrayAdapter<CharSequence> adapter_wallpaper;
ArrayAdapter<CharSequence> adapter_event;
ArrayAdapter<CharSequence> adapter_activity;
Button startButton;
String textActivity;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.content_admin);


    spinner_event = (Spinner)findViewById(R.id.spinner_event);
    adapter_event = ArrayAdapter.createFromResource(this, R.array.events,android.R.layout.simple_spinner_dropdown_item);
    spinner_event.setAdapter(adapter_event);


    spinner_activity = (Spinner)findViewById(R.id.spinner_activity);
    adapter_activity = ArrayAdapter.createFromResource(this, R.array.activity,android.R.layout.simple_spinner_dropdown_item);
    spinner_activity.setAdapter(adapter_activity);


    spinner_wallpaper = (Spinner)findViewById(R.id.spinner_wallpaper);
    adapter_wallpaper = ArrayAdapter.createFromResource(this, R.array.wallpapers,android.R.layout.simple_spinner_dropdown_item);
    spinner_wallpaper.setAdapter(adapter_wallpaper);

    startButton = (Button)findViewById(R.id.startButton);
    startButton.setOnClickListener(this);
    }

@Override
public void onClick(View v) {
    textActivity = spinner_activity.getSelectedItem().toString();
    switch(v.getId()){

        case R.id.startButton:
        {
            if(textActivity == "Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            break;
        }
    }
}
}

我应该去我的 BadgeEntree。它们都在 AndroidManifest.xml 上定义，我很迷茫，一切似乎都很好，但事实并非如此，我做错了什么？

感谢您的帮助

Answer 1

从您的按钮 xml 代码中删除 onClick 标记

Answer 2

在 xml

中删除 android:onClick="jumpTo"

<Button
android:layout_width="wrap_content"
android:layout_height="wrap_content"
android:text="@string/lancer"
android:id="@+id/startButton"
android:layout_alignParentRight="true"
android:layout_alignParentBottom="true"
android:clickable="true"
/>

Answer 3

你必须删除这一行

  <Button
    android:layout_width="wrap_content"
    android:layout_height="wrap_content"
    android:text="@string/lancer"
    android:id="@+id/startButton"
    android:layout_alignParentRight="true"
    android:layout_alignParentBottom="true"
    android:clickable="true"
    android:onClick="jumpTo" <-----

/>

并在您的 class 中移动 jumpTo 方法的逻辑，因为现在您在 class 和 xml 中有了 onCLick 侦听器。同时更改此行

if(textActivity == "Entree")

有了这个..

if(textActivity.equals("Entree"))

Answer 4

if(textActivity == "Entree")

将上面的代码更改为

if(textActivity.equalsIgnoreCase("Entree"))

同时从您的 xml

中删除以下代码

android:onClick="jumpTo"

注意： 如果您想要不区分大小写的字符串比较，您可以使用 "equalsIgnoreCase"，如果您想要区分大小写的字符串比较，那么您可以使用 "equals".

Answer 5

删除

     startButton.setOnClickListener(this);
    }

@Override
public void onClick(View v) {
    textActivity = spinner_activity.getSelectedItem().toString();
    switch(v.getId()){

        case R.id.startButton:
        {
            if(textActivity == "Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            break;
        }
    }

做

一开始你应该调用 if(textActivity.equals("Entree") 而不是 ==

仅供参考

Now, when you clicks the button, the Android system calls the activity's jumpTo(View) method. In order for this to work, the method must be public and accept a View as its only parameter.

public void jumpTo(View i)
{
textActivity = spinner_activity.getSelectedItem().toString();
if(textActivity.equals("Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            else
            {
            Log.d("Else","Wrong");
            }
}

终于

public class Admin extends AppCompatActivity  {

Spinner spinner_event;
Spinner spinner_activity;
Spinner spinner_wallpaper;
ArrayAdapter<CharSequence> adapter_wallpaper;
ArrayAdapter<CharSequence> adapter_event;
ArrayAdapter<CharSequence> adapter_activity;
Button startButton;
String textActivity;


@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);

    setContentView(R.layout.content_admin);


    spinner_event = (Spinner)findViewById(R.id.spinner_event);
    adapter_event = ArrayAdapter.createFromResource(this, R.array.events,android.R.layout.simple_spinner_dropdown_item);
    spinner_event.setAdapter(adapter_event);


    spinner_activity = (Spinner)findViewById(R.id.spinner_activity);
    adapter_activity = ArrayAdapter.createFromResource(this, R.array.activity,android.R.layout.simple_spinner_dropdown_item);
    spinner_activity.setAdapter(adapter_activity);


    spinner_wallpaper = (Spinner)findViewById(R.id.spinner_wallpaper);
    adapter_wallpaper = ArrayAdapter.createFromResource(this, R.array.wallpapers,android.R.layout.simple_spinner_dropdown_item);
    spinner_wallpaper.setAdapter(adapter_wallpaper);

    startButton = (Button)findViewById(R.id.startButton);

    }


public void jumpTo(View i)
{
textActivity = spinner_activity.getSelectedItem().toString();
if(textActivity.equals("Entree"){
                Intent i = new Intent(this, BadgeEntree.class);
                startActivity(i);
            }
            else
            {
            Log.d("Else","Wrong");
            }
}


}

onClick 事件不起作用 Android

onClick event don't work Android

java

android

onclick

button

spinner

仅供参考