breadth_first_search 在 labeled_graph

Question

假设以下设置，应该如何使用 labeled_graph 调用 breadth_first_search？ - 导致 2 个错误：

二进制“[”: 未找到接受 'Vertex' 类型右手操作数的运算符（或没有可接受的转换）

'.id' 左边的错误 2 必须有 class/struct/union

#include<iostream>
#include<boost/graph/adjacency_list.hpp>
#include<boost/graph/breadth_first_search.hpp>
#include <boost/graph/labeled_graph.hpp>

using namespace boost;

struct NodeInfo{int id;};
struct EdgeInfo{};

typedef boost::labeled_graph< boost::adjacency_list<
    boost::vecS, boost::vecS, boost::undirectedS, NodeInfo, EdgeInfo>,
    std::string> Graph;

typedef boost::graph_traits<Graph>::vertex_descriptor GridVertex;

class Topology 
{
public:

    Graph grid;
    std::map<std::string, GridVertex> vertices; //_id to Edge

    struct custom_visitor : public boost::default_bfs_visitor
    {
        Graph& grid;

        custom_visitor(Graph& grid) :grid(grid)  {}

        template <typename Vertex, typename Graph>
        void discover_vertex(Vertex v, const Graph& g)
        {

            //vertex(...) in breadth_first_search is causing: 
            //binary '[' : no operator found which takes a right-hand operand of 
            //type 'Vertex' (or there is no acceptable conversion)  
            //left of .id must have class...
            int m = grid[v].id;

        }
    };

    void GetShortestPath(std::string s_id, std::string t_id)
    {
        custom_visitor vis(grid);

        //vertex(...) causes error
        breadth_first_search(grid.graph(), vertex(vertices[s_id],grid.graph()), visitor(vis));
    }

    void BuildNet()
    {
        Graph g;
        GridVertex v;

        v = add_vertex("A", NodeInfo(), g);
        vertices["A"] = v;

        v = add_vertex("B", NodeInfo(), g);
        vertices["B"] = v;

        add_edge_by_label("A", "B", EdgeInfo(), g);
    }
};


int main()
{
    Topology net;
    net.GetShortestPath("A", "B");
    return 0;
}

Answer 1

为什么要使用 labeled_graph？

带标签的图表与只是 adjacency_list 有不同的界面。这并不奇怪，因为否则还有什么意义:)

所以，如果 vertex(...) causes error 使用 grid.vertex(s_id):

breadth_first_search(grid.graph(), grid.vertex(s_id), visitor(vis));

在访问者中，使用实际图表，以便您可以使用其 operator[]:

int m = grid.graph()[v].id;

或者，实际上为什么不使用第二个参数，目的是：

void discover_vertex(Vertex v, const Graph& g) {
    int m = g[v].id;
}

努力从代码中做出一个合理的例子：Live On Coliru

breadth_first_search 在 labeled_graph

breadth_first_search on labeled_graph

c++

boost-graph