MySQL有限结果后的一行总和

Question

我有这个 User table:

+----------+-------+
| Username | Value |
+----------+-------+
| User4    |     2 |
| User1    |     3 |
| User3    |     1 |
| User2    |     6 |
| User4    |     2 |
+----------+-------+

然后我执行此查询以获得前 2 名的总和：

SELECT Username, SUM(Value) AS Sum
FROM User
GROUP BY Username
ORDER BY Sum DESC
LIMIT 0, 2

结果是：

+----------+-----+
| Username | Sum |
+----------+-----+
| User2    |   6 |
| User4    |   4 |
+----------+-----+

我正在寻找的是 另外一行给出所有值的总和，例如：

+----------+-----+
| Username | Sum |
+----------+-----+
| User2    |   6 |
| User4    |   4 |
| All      |  14 |
+----------+-----+

有什么办法可以实现吗？最好不用任何程序。

Answer 1

使用联合

SELECT Username, SUM(Value) AS Sum
FROM User
GROUP BY Username
ORDER BY Sum DESC
LIMIT 0, 2
union 
SELECT'ALL', SUM(Value) AS Sum
FROM User

Answer 2

使用 UNION ALL 来做到这一点。

(SELECT Username, SUM(Value) AS Sum
FROM User
GROUP BY Username
ORDER BY Sum DESC
LIMIT 0, 2)
UNION ALL
(SELECT 'All', SUM(Value) AS Sum FROM User)

Answer 3

您可以使用 WITH ROLLUP 修饰符：

SELECT COALESCE(Username, 'All'), SUM(Value) AS Sum
FROM User
GROUP BY Username WITH ROLLUP
ORDER BY Sum DESC

或者，如果您只想要前 2 名以及所有的总和：

 SELECT Username, s
 FROM (
    SELECT Username, s
    FROM (
      SELECT COALESCE(Username, 'All') AS Username, SUM(Value) AS s
      FROM User
      GROUP BY Username WITH ROLLUP  ) AS t
    ORDER BY s DESC      
    LIMIT 0, 3) AS s
 ORDER BY IF(Username = 'All', 0, s) DESC

MySQL有限结果后的一行总和

MySQL one row of sum after limited results

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