Javascript 对象映射（展平）

Question

您好，我有一个使用 JSON.Stringify

输出到此的对象

{"0":["test1","ttttt","","","","","","","",""],"1":["test2","ghjgjhgjh","","","","","","","",""]}

我想要这样的输出。

[["test1","ttttt","","","","","","","",""],["test2","ghjgjhgjh","","","","","","","",""]]

我试过使用 .map

删除“0”和“1”

var itemjson = $.map(cleanedGridData, function (n) {
        return n;
    });

然而，这给出了（下图）的输出，它已经变平了。

["test1", "ttttt", "", "", "", "", "", "", "", "", "test2", "ghjgjhgjh", "", "", "", "", "", "", "", ""]

Answer 1

更改您的 return 语句以将 n 放入另一个数组。

return [n];

这是因为 jQuery 的 $.map 将您 return 的数组扁平化为结果，因此您需要将其包裹在外部数组中。

要么，要么只使用 for in 循环。

var itemjson = [];
for (var key in cleanedGridData) {
  itemjson.push(cleanedGridData[key]);
}

Answer 2

您可以使用它来提取值：

var res = {"0":["test1","ttttt","","","","","","","",""],"1":["test2","ghjgjhgjh","","","","","","","",""]}
Object.keys(res).map(function(key) {
    return res[key];
});

Object.keys 将列出初始对象中的所有键。然后，您可以使用 map 遍历这些键并在该函数中提取值。

Answer 3

一旦您的环境（即在浏览器的情况下，您想要支持的所有浏览器）都有 Object.values (and spread operator）可用，您可以去

[...Object.values(cleanedGridData)]

Javascript 对象映射（展平）

Javascript Object Map (flatten)

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dictionary

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