为什么对象总是将自己定位为@ 0.0 而不是最初生成的对象

Question

使用此代码生成：

GameObject goX = Resources.Load ("Apple") 作为游戏对象； GameObject goY = Resources.Load ("Orange") 作为游戏对象； GameObject goZ = Resources.Load ("Banana") as GameObject;

    GameObject go1 = GameObject.Instantiate (goX, Spawn3.transform.position, Quaternion.identity) as GameObject; 
    NetworkServer.Spawn (go1);
    GameObject go2 = GameObject.Instantiate (goY, Spawn4.transform.position, Quaternion.identity) as GameObject; 
    NetworkServer.Spawn (go2);
    GameObject go3 = GameObject.Instantiate (goZ, Spawn1.transform.position, Quaternion.identity) as GameObject; 
    NetworkServer.Spawn (go3);

Spawn1 - Spawn4 不是 0.0

生成对象时，它生成在正确的位置，但随后立即移动到 0.0 位置。

这是我在对象上使用的同步脚本，我认为问题出在脚本中，因为当我使用它工作的 NetworkTransform 组件时。但是，NetworkTransform 遗漏了一些动作，所以我想在脚本中同步：

using UnityEngine;
using System.Collections;
using UnityEngine.Networking;

public class Object_SyncPosition : NetworkBehaviour {

private Transform myTransform;
[SerializeField] float lerpRate = 15;
[SyncVar] private Vector3 syncPos;

void Start () {
    myTransform = GetComponent<Transform> ();
}

void Update () {
    if (hasAuthority) {
        TransmitPosition ();
    }

    LerpPosition ();

}

void LerpPosition () {
    if (!isLocalPlayer) {
        myTransform.position = Vector3.Lerp (myTransform.position, syncPos, Time.deltaTime * lerpRate);
    }
}

[Command]
void Cmd_ProvidePositionToServer (Vector3 pos) {
    syncPos = pos;
}

[ClientCallback]
void TransmitPosition () {
    Cmd_ProvidePositionToServer (myTransform.position);
}

}

Answer 1

我认为您的对象正在向您的 syncPos 移动（默认情况下为 0.0）。尝试在启动脚本中将 syncPos 转换设置为您的重生位置。

void Start () {
    myTransform = GetComponent<Transform> (); 
    syncPos = GetComponent<Transform>().position;
}

为什么对象总是将自己定位为@ 0.0 而不是最初生成的对象

Why is the object always position itself @ 0.0 and not were it is originally spawned

unity3d

multiplayer

unity3d-unet