使用 PHP 获取 <script type="application/ld+json"> 的内容

Question

我找不到 API Vine 来获取页面内容的标题、描述和图像。 JSON 位于页面本身的 body 脚本标记中：。如何使用 PHP 获取此脚本标记的内容（JSON）以便对其进行解析？

藤页：

https://vine.co/v/igO3EbIXDlI

来自页面源

<script type="application/ld+json">
            {
              "@context": "http://schema.org",
              "@type": "SocialMediaPosting",
              "url": "https://vine.co/v/igO3EbIXDlI",
              "datePublished": "2016-03-01T00:58:35",
              "author": {
                "@type": "Person",
                "name": "MotorAddicts\u2122",
                "image": "https://v.cdn.vine.co/r/avatars/39FEFED72B1242718633613316096_pic-r-1439261422661708f3e9755.jpg.jpg?versionId=LPjQUQ4KmTIPLu3iDbXw4FipgjEpC6fw",
                "url": "https://vine.co/u/989736283540746240"
              },
              "articleBody": "Mmm...  Black black blaaaaack!! \ud83d\ude0d ( Drift \u53d1 )",
              "image": "https://v.cdn.vine.co/r/videos/98C3799A811316254965085667328_SW_WEBM_14567938452154dc600dbde.webm.jpg?versionId=wPuaQvDxnpwF7KjSGao21hoddooc3eCl",
              "interactionCount": [{
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserLikes",
                "value": "1382"
              }, {
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserShares",
                "value": "368"
              }, {
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserComments",
                "value": "41"
              }, {
                "@type": "UserInteraction",
                "userInteractionType": "http://schema.org/UserViews",
                "value": "80575"
              }],

              "sharedContent": {
                "@type": "VideoObject",
                "name" : "Mmm...  Black black blaaaaack!! \ud83d\ude0d ( Drift \u53d1 )",
                "description" : "",
                "thumbnailUrl" : "https://v.cdn.vine.co/r/videos/98C3799A811316254965085667328_SW_WEBM_14567938452154dc600dbde.webm.jpg?versionId=wPuaQvDxnpwF7KjSGao21hoddooc3eCl",
                "uploadDate" : "2016-03-01T00:58:35",
                "contentUrl" : "https://v.cdn.vine.co/r/videos_h264high/98C3799A811316254965085667328_SW_WEBM_14567938452154dc600dbde.mp4?versionId=w7ugLPYtj5LWeVUsXaH1bt2VuK8QE0qv",
                "embedUrl" : "https://vine.co/v/igO3EbIXDlI/embed/simple",
                "interactionCount" : "82366"
              }
            }
          </script>

这之后要做什么？

$html = 'https://vine.co/v/igO3EbIXDlI';
$dom = new DOMDocument;
$dom->loadHTML($html);

更新：

我在此处找到了 Vine API 的说明：

https://dev.twitter.com/web/vine/oembed

要为 JSON 查询 Vine API，请从以下位置获取请求：

https://vine.co/oembed.json?url=https%3A%2F%2Fvine.co%2Fv%2F[videoid]

示例：

https://vine.co/oembed.json?url=https%3A%2F%2Fvine.co%2Fv%2FMl16lZVTTxe

Answer 1

$html_content = file_get_contents('https://vine.co/v/igO3EbIXDlI');

$target_class = 'script';

$dom_object = new DOMDocument;
$dom_object->loadHTML($html_content);
$xpath_object = new DOMXpath($dom_object);

$elements = $xpath_object->query("//*[contains(concat(' ', normalize-space(@class), ' '), ' {$target_class} ')]");

$output = []
foreach ($elements as $element)
{
    $output[] = $dom_object->saveHTML($element);
}

# you now have a list of strings, each containing the contents of a 
# non-overlapping script tag

Answer 2

您可以为此使用 DOMDocument 和 DOMXpath：

$html = file_get_contents( $url );
$dom  = new DOMDocument();
libxml_use_internal_errors( 1 );
$dom->loadHTML( $html );
$xpath = new DOMXpath( $dom );
$jsonScripts = $xpath->query( '//script[@type="application/ld+json"]' );
$json = trim( $jsonScripts->item(0)->nodeValue );

$data = json_decode( $json );

phpFiddle demo

使用此 xPath 模式，您可以搜索属性 type 为“application/ld+json”的所有 <script> 节点：

//                              Following path no matter where they are in the document
script                          Elements <script>
[@type="application/ld+json"]   with attribute “tipe” as “application/ld+json”

然后您检索您的 JSON 字符串，获取第一个返回的 <script> 节点的 ->nodeValue。

如果你事先不知道节点存在and/or它的位置，使用这个：

$jsonScripts = $xpath->query( '//script[@type="application/ld+json"]' );
if( $jsonScripts->length < 1 )
{
    die( "Error: No script node found" );
}
else
{
    foreach( $jsonScripts as $node )
    {
        $json = json_decode( $node->nodeValue );

        // your stuff with JSON ...
    }
}

使用 PHP 获取 <script type="application/ld+json"> 的内容

Get content of <script type="application/ld+json"> using PHP

php

parsing

json

vine