javax.ws.rs.NotFoundException: 找不到完整路径的资源发生错误

Question

我在这里发现了几次同样的问题，但找不到答案。

当我运行我的应用程序时，我收到以下错误

javax.ws.rs.NotFoundException: Could not find resource for full path: http://localhost:8080/RemoteQuartzScheduler/rest/TestClass/hello
    at org.jboss.resteasy.core.registry.ClassNode.match(ClassNode.java:73)
    at org.jboss.resteasy.core.registry.RootClassNode.match(RootClassNode.java:48)
    at org.jboss.resteasy.core.ResourceMethodRegistry.getResourceInvoker(ResourceMethodRegistry.java:444)
    at org.jboss.resteasy.core.SynchronousDispatcher.getInvoker(SynchronousDispatcher.java:234)
    at org.jboss.resteasy.core.SynchronousDispatcher.invoke(SynchronousDispatcher.java:171)
    at org.jboss.resteasy.plugins.server.servlet.ServletContainerDispatcher.service(ServletContainerDispatcher.java:220)
    at org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher.service(HttpServletDispatcher.java:56)
    at org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher.service(HttpServletDispatcher.java:51)
    at javax.servlet.http.HttpServlet.service(HttpServlet.java:728)
    at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:305)
    at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:210)
    at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:222)
    at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:123)
    at org.apache.catalina.authenticator.AuthenticatorBase.invoke(AuthenticatorBase.java:502)
    at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:171)
    at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:99)
    at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:953)
    at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:118)
    at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:408)
    at org.apache.coyote.http11.AbstractHttp11Processor.process(AbstractHttp11Processor.java:1023)
    at org.apache.coyote.AbstractProtocol$AbstractConnectionHandler.process(AbstractProtocol.java:589)
    at org.apache.tomcat.util.net.JIoEndpoint$SocketProcessor.run(JIoEndpoint.java:310)
    at java.util.concurrent.ThreadPoolExecutor.runWorker(ThreadPoolExecutor.java:1110)
    at java.util.concurrent.ThreadPoolExecutor$Worker.run(ThreadPoolExecutor.java:603)
    at java.lang.Thread.run(Thread.java:722)

这里是项目的pom文件（我只加了主要部分）

<repositories>
    <repository>
        <id>JBoss repository</id>
        <url>https://repository.jboss.org/nexus/content/groups/public-jboss/</url>
    </repository>
</repositories>
<dependencies>
    <dependency>
        <groupId>junit</groupId>
        <artifactId>junit</artifactId>
        <version>3.8.1</version>
        <scope>test</scope>
    </dependency>
    <dependency>
        <groupId>org.jboss.resteasy</groupId>
        <artifactId>resteasy-jaxrs</artifactId>
        <version>3.0.9.Final</version>
    </dependency>
    <dependency>
        <groupId>org.jboss.resteasy</groupId>
        <artifactId>resteasy-servlet-initializer</artifactId>
        <version>3.0.9.Final</version>
    </dependency>
</dependencies>

这是我的 web.xml 文件

<web-app version="3.0" xmlns="http://java.sun.com/xml/ns/javaee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd">


<display-name>RemoteQuartzScheduler</display-name>

<servlet-mapping>
    <servlet-name>resteasy-servlet</servlet-name>
    <url-pattern>/rest/*</url-pattern>
</servlet-mapping>


<!-- this should be the same URL pattern as the servlet-mapping property -->
<context-param>
    <param-name>resteasy.servlet.mapping.prefix</param-name>
    <param-value>/rest</param-value>
</context-param>

<listener>
    <listener-class>
        org.jboss.resteasy.plugins.server.servlet.ResteasyBootstrap
        </listener-class>
</listener>

<servlet>
    <servlet-name>resteasy-servlet</servlet-name>
    <servlet-class>
        org.jboss.resteasy.plugins.server.servlet.HttpServletDispatcher
    </servlet-class>
</servlet>

这是我的Test.javaclass

@Path("/TestClass")
public class Test implements Serializable{

  private static final long serialVersionUID = -262701666015379272L;

  @GET
  @Path("/hello")
  public Response heloMessage() {

    String result = "Hello Word!!!!!!!!!";

    return Response.status(200).entity(result).build();
  }   
}

请问我哪里做错了？？提前致谢

Answer 1

我还没有机会测试你的版本（使用 web.xml），老实说，当我做使用 Resteasy，所以我不会试图解释 web.xml.

有什么问题（如果有的话）

但是在使用 javax.xs.rs.core.Application 子类时，我们可以定义一个 @ApplicationPath("/path") 注释。这为我们的 JAX-RS 应用程序定义了一个 servlet，具有 /path/* 的 url 映射。这是在 JAX-RS 规范中指定的。

您可以在此处的 2.3.2 Configuration - Servlet. This is a 1.1 spec (you are using 2.0), but the deployment options are similar. I just couldn't find an html link to the 2.0. You can download the pdf though from here.

部分中查看有关此部署选项以及其他选项的更多信息

您还可以阅读有关使用 Resteasy 进行部署的更多信息 here in the documentation。

但基本上，此部署选项的作用是扫描应用程序的 @Path、@Provider 等注释。原因是 JAX-RS 将首先分别在覆盖的 getClasses() 和 getSingletons() 中查找类和对象。如果然后 return 空集，这告诉 JAX-RS 进行扫描（根据规范）。

javax.ws.rs.NotFoundException: 找不到完整路径的资源发生错误

javax.ws.rs.NotFoundException: Could not find resource for full path Error Occures

java

rest

web-services

jax-rs

maven