删除 SQL where 子句中的 + - 值记录

Question

我需要删除 + - 值记录意味着

我只需要输出中的蓝色两条记录 windows。希望它清楚我到底想要什么。

User5   |  -15
User6   |  -10

Answer 1

想法是获取第二列（在我的例子中是 Val）被抵消的行。您可以通过获取绝对值并分配按绝对值和值本身分组的行号来实现。那些没有匹配的行号应该是结果。

WITH SampleData(UserID, Val) AS(
    SELECT 'User1', -10 UNION ALL
    SELECT 'User2', 10 UNION ALL
    SELECT 'User3', -15 UNION ALL
    SELECT 'User4', -10 UNION ALL
    SELECT 'User5', -15 UNION ALL
    SELECT 'User6', -10 UNION ALL
    SELECT 'User7', 10 UNION ALL
    SELECT 'User8', 15 
)
,Numbered AS(
    SELECT
        UserID,
        Val,
        BaseVal = ABS(Val),
        RN = ROW_NUMBER() OVER(PARTITION BY ABS(Val), Val ORDER BY UserId)
    FROM SampleData
)
SELECT 
    n1.UserID,
    n1.Val
FROM Numbered n1
LEFT JOIN Numbered n2 
    ON n2.BaseVal = n1.BaseVal
    AND n2.RN = n1.rn
    AND n2.UserID <> n1.UserID
WHERE n2.UserID IS NULL
ORDER BY n1.UserID

Answer 2

您似乎想要总计不等于 0 的行？

    select 
      userName, 
      userValue 
    from 
      yourTable
    where 
      userName in (
      select userName from yourTable 
      group by userName 
      having sum (userValue) <> 0
    )

删除 SQL where 子句中的 + - 值记录

Remove + - value records in SQL where clause

sql

sql-server

sql-server-2008-r2

sql-server-2012